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Gennadij [26K]
3 years ago
8

96oz __ 5 lb greater than, less than, or equal to

Mathematics
1 answer:
lys-0071 [83]3 years ago
8 0
96 oz is greater than 5 lb
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Uniform circular motion is used in physics to describe the motion of an object traveling at a constant speed in a circle. The sp
Ivanshal [37]

Answer:

  B)  T = 2πr/v

Step-by-step explanation:

To solve the given equation for T, multiply it by T/v.

v=\dfrac{2\pi r}{T}\\\\v\dfrac{T}{v}=\dfrac{2\pi r}{T}\cdot\dfrac{T}{v}\\\\T=\dfrac{2\pi r}{v} \qquad\text{simplify}

6 0
3 years ago
A chef kept track of the number of apples people ate last week in his cafeteria. The results are shown here.
n200080 [17]
The correct answer is C) 10
5 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
In 1 and 2, use the table below that shows information about squares.
frutty [35]

1. The table has a constant of proportionality of 4, therefore, the perimeter and side length of squares are proportional.

2. Equation for the proportion is, y = 4x.

Perimeter = 48 cm.

<h3>What is the Equation of a Proportional Relationship?</h3>

The equation that defines a proportional relationship is, y = kx, where k is the constant of proportionality between variables x and y.

1. For the table given:

y = perimeter

x = side length

k = constant of proportionality = 8/2 = 16/4 = 24/6 = 4.

Since k is the same all through, the equation can be modelled as y = 4x, which means the perimeter and side length of squares are proportional.

2. Using the equation, y = 4x,the perimeter (y) of a square when its side length is 12 (x) is:

y = 4(12)

y = 48 cm.

The perimeter (y) of the square is: 48 cm.

Learn more about proportional relationship on:

brainly.com/question/15618632

#SPJ1

3 0
2 years ago
2. An expression is shown below.
velikii [3]
The answer is B12 hope this helped
5 0
3 years ago
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