1. 0.01333
2. 0.29069767
3. 0.45977011
Answer:
a) 0.69
The probability that a randomly selected 10-year old child will be more than 51.75 inches tall
P(X>51.75 ) = 0.6915
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
<em>Given mean of the Population = 54.6 inches</em>
<em>Given standard deviation of the Population = 5.7 inches</em>
<em>Let 'X' be the random variable of normal distribution</em>
Let 'X' = 51.75 inches

<u><em>Step(ii):</em></u>-
<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>
<em>P(X>51.75 ) = P(Z>-0.5)</em>
= 1 - P( Z < -0.5)
= 1 - (0.5 - A(-0.5))
= 1 -0.5 + A(-0.5)
= 0.5 + A(0.5) (∵A(-0.5)= A(0.5)
= 0.5 +0.1915
= 0.6915
<u><em>Conclusion</em></u>:-
<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>
<em>P(X>51.75 ) = 0.6915</em>
Step-by-step explanation:
3/5x+22=28
3/5x=28-22
3/5x=6
3x=6*5
3x=30
X=30/3
X=10
Answer:
question (1)
height of building = 308 ft
question (2)
cos 67.11 = 7/18
Explanation:
question (1)
Taking a look at the triangle, we can see that it is a right-angled triangle. This means that we can apply the special trigonometric identities.
The one we will use here is:
tan Θ = opposite / adjacent
where:
Θ = 72
the opposite side is the height of the building
the adjacent side = 100 ft
Substitute to get the height as follows:
tan(72) = height / 100
height = tan(72)*100 = 307.76 which is approximately 308 ft
question (2):
We are given that:
cos Θ = 7/18
therefore:
Θ = cos^-1(7/18)
Θ = 67.114
approximating to the nearest tenth, we would find that:
Θ = 67.11°
Hope this helps :)
(p+3q)(p+8q) is your answer