Answer:
3
Step-by-step explanation
Your problem statement tells you
f(x) passes through point (3, negative 1)
g(x) passes through point (3, negative 1)
This tells you the input value that produces the same output value for the two functions is 3, and that output value is -1.
Answer:
Relative frequency of selecting a 2 = 8/50 = 0.16
Relative frequency of selecting a 3 = 14/50 = 0.28
Step-by-step explanation:
When we have a given experiment with given outcomes (such that each time that we perform the experiment, one outcome happens) the relative frequency of a given outcome is the quotient between the number of times that that outcome happened, and the total number of times that the experiment was performed.
Here the experiment is selecting a random number between 1 and 5, and it is performed 50 times.
Out of these 50 times, the outcome "2" appears 8 times.
Then the relative frequency of selecting the number 2 is:
f(2) = 8/50 = 0.16
And of these 50 experiments, the outcome "3" appears 14 times.
Then the relative frequency of selecting the number 3 is:
f(3) = 14/50 = 0.28
<h3>
Answers:</h3>

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Explanation:
The scale factor is 2, which means we double each coordinate of each point. The general rule is
with k = 2. So we can say the more specific dilation rule is 
Something like W(-2,2) moves to W ' (-4, 4) after multiplying each coordinate by 2. Do the same for the other points as well.
The given preimage points
- V = (-2, -1)
- W = (-2, 2)
- X = (0, 2)
- Y = (3, -1)
will dilate to the corresponding image points
- V ' = (-4, -2)
- W ' = (-4, 4)
- X ' = (0, 4)
- Y ' = (6, -2)
as shown below. This causes the image to be larger compared to the preimage (since the scale factor is larger than 1). Any given point is twice as far from the origin as compared to before, which in turn means the distance between any two points is twice as much.
Subtract x on both sides the result you divide it by 5
Answer:
D
Step-by-step explanation: