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DedPeter [7]
3 years ago
9

Plz help with this math. Can't find the area of the triangular faces.

Mathematics
1 answer:
Zina [86]3 years ago
4 0
First of all, you have to find the area of both triangles:
\frac{bh}{2}
\frac{4*4}{2}
Or just 16 because there are 2 of the same triangles.

Now you have to find the area of the 3 rectangles.

The two that are in the front are 4*3 (l*h) or 12*2 (because there are 2 congruent rectangles. The area of those rectangles is 24 square mm.

Now you find the area of the back rectangle:
5.7*3 = 17.1

Finally, you add all the found numbers to figure out the surface area.
17.1 + 16 + 24 = 57.1 square millimeters.

Hope this helped,
Loafly
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For this case we must find the solution of the following quadratic equation:

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Then, the solution is given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

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x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}

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Can someone help me understand this pls? (Provide an explanation)
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Step-by-step explanation:

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