A circle with radius 4 inches is inscribed in an equilateral triangle. Find the area of the triangle.
1 answer:
The inscribed circle has its center at the point of intersection of the angle bisectors, which also happen to be the medians. Hence the altitude of the triangle is 3 times the radius, or 12 inches.
The side length of this triangle is 2/√3 times the altitude, so the area is
... Area = (1/2)·b·h = (1/2)·(24/√3 in)·(12 in)
... Area = 48√3 in² ≈ 83.1384 in²
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<h2>Ratio of area of the square to the area of the circle = π/4</h2>
Step-by-step explanation:
Let the side of square be a and radius of circle be r.
The perimeter of a particular square and the circumference of a particular circle are equal.
Perimeter of square = 4 x a = 4a
Circumference of circle = 2πr
Given that
4a = 2πr
We need to find the ratio of the area of the square to the area of the circle.
Area of the square = a²
Area of the circle = πr²
Ratio of area of the square to the area of the circle = π/4
First get all the terms on the same side:
Now solve using the quadratic formula which is:
Plug in the values:
So the answer is:
Now solve using the quadratic formula which is:
Plug in the values:
So the answer is: