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MAXImum [283]
3 years ago
6

A circle with radius 4 inches is inscribed in an equilateral triangle. Find the area of the triangle.

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

The inscribed circle has its center at the point of intersection of the angle bisectors, which also happen to be the medians. Hence the altitude of the triangle is 3 times the radius, or 12 inches.

The side length of this triangle is 2/√3 times the altitude, so the area is

... Area = (1/2)·b·h = (1/2)·(24/√3 in)·(12 in)

... Area = 48√3 in² ≈ 83.1384 in²

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3 years ago
I need help with number 5
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Answer:

-6 is the answer.

Step-by-step explanation:

4x - 5 = x - 23

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or, 3x = -18

or, x = -18/3

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5 0
3 years ago
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