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OLEGan [10]
3 years ago
6

A basketball coach uses a coordinate grid to mark the position and

Mathematics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

Step-by-step explanation:

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the copy machine at the library made a copy of leslie's 3 page essay in just 1/10 of a minute. what is the speed of the copy mac
borishaifa [10]

Answer:

<h2><em>30page essay/min</em></h2>

Step-by-step explanation:

Speed is the change in distance of a body with respect to time.

Speed = Distance/Time

If the library made a copy of leslie's 3 page essay in just 1/10 of a minute, this means that she made 3 pages in (1/10 * 60)secs i.e 6secs

To get the speed, we need to calculate the amount of page of essay that are produced in a minute (60secs).

If 3 page essay = 6secs

x page essay = 60 secs

cross multiply

3*60 = 6x

180 = 6x

x = 180/6

x = 30

<em>This shows that 30 page essays are produced in just a minute. Hence the speed of the copy machine is 30page essay/min.</em>

5 0
3 years ago
Whats 7x in algebraic expression
kozerog [31]
Coefficient is the correct answer
5 0
3 years ago
1 3/5 + 2 5/10 what does that equal
Strike441 [17]

Answer:

Step-by-step explanation:

1 3/5 + 2 5/10 = 26/10 +25/10 = 51/10

5 0
3 years ago
Read 2 more answers
A bird with a mass of 1.5 kg flies at a rate of 4.0 m/s. What is the kinetic energy of the bird?
weqwewe [10]
The answer is 12 J.

The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):
KE =  \frac{1}{2} m*v^{2}

The unit of the kinetic energy is Joules (J = kg · (m/s)²).

It is given:
m = 1.5 kg
v = 4 m/s

It is unknown:
KE = ?

Thus:
KE = \frac{1}{2} m*v^{2}
<span>KE = \frac{1}{2} 1.5kg*(4 m/s)^{2}</span>
<span>KE = 0.75kg*16(m/s)^{2}</span>
KE = 12 kg*(m/s)^{2}
KE = 12J

Therefore, the kinetic energy of the bird is 12J.
3 0
3 years ago
Read 2 more answers
A curcular track is 1/4 completing each mile every 1/15 mile
dsp73

Answer:

s = 3.75 miles/hour

Step-by-step explanation:

Distance covered = 1/4 of a mile

Time taken = 1/15 of an hour

We need to find the speed of the track. We know that,

s=\dfrac{d}{t}\\\\=\dfrac{\dfrac{1}{4}}{\dfrac{1}{15}}\\\\=3.75\ mi/h

So, the required speed is 3.75 miles/hour.

4 0
3 years ago
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