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3 years ago

Find x to the nearest whole number

Mathematics

1 answer:

DENIUS [597]3 years ago

3 0

Answer:

Step-by-step explanation:

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What is the answer to this problem?

Amanda [17]

Answer:

B.) Transitive Property of Congruency; If parallel lines have a transversal, then alternative interior angles are congruent.

Step-by-step explanation:

Alternate interior angles are the two angles that are inbetween the parallel lines but are on opposite sides of the transversal. Angles 4 and 5 are alternate interior, and therefore, they are congruent.

7 0

3 years ago

The base of a rectangular prism is 7 cm long,and 5 cm wide. If the surface area of the prism

Phantasy [73]

Answer:

V=280

Step-by-step explanation:

7·5=35

310\35 = 8.8

V=whl=5·8·7=280

4 0

2 years ago

Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =

marissa [1.9K]

In Cartesian coordinates, the region is given by $-3\le x\le3$ , $-\sqrt{9-x^2}\le y\le\sqrt{9-x^2}$ , and $-\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}$ . Converting to cylindrical coordinates, using

$\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}$

we get a Jacobian determinant of $r$ , and the region is given in cylindrical coordinates by $0\le\theta\le2\pi$ , $0\le r\le3$ , and $-\sqrt{16-r^2}\le z\le\sqrt{16-r^2}$ .

The volume is then

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3$

6 0

3 years ago

What is the combine like terms of 3(12x-x

steposvetlana [31]

Step-by-step explanation:

33x

7 0

3 years ago

How do you find the equations of the vertical and horizontal asymptotes for a graph when you only have the graph and no function

-BARSIC- [3]

Answer:

See below for answer and explanations (as well as an attached graph)

Step-by-step explanation:

Pay attention to the behavior of the asymptotes. If the asymptotes are approaching a certain x-value or y-value, then that value is undefined for the function.

Take for example $y=\frac{1}{x}$ :

As x approaches ∞ and -∞, then y approaches 0, which is our horizontal asymptote

As y approaches ∞ and -∞, then x approaches 0, which is our vertical asymptote

See the graph for a visual.

8 0

2 years ago