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3 years ago

Number 16 a b and c please

Mathematics

1 answer:

zlopas [31]3 years ago

4 0

A. 1/6

b. 6/3

c. 1

I think those are the answers

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Need help doing this questions, all help is appreciated thanks.

vichka [17]

Answer:

The answer to your question is the third option

Step-by-step explanation:

To know if two lines are parallel we must get their slopes if the slopes are equal, the lines are parallel.

Data

A (2,2)

B (3,6)

C(0,5)

D(1,9)

Formula

slope = $\frac{y2 - y1}{x2 - x1}$

Process

1.- Calculate the slope of line 1

slope 1 = $\frac{6 - 2}{3 - 2}$

slope 1 = $\frac{4}{1}$

slope 1 = 4

2.- Calculate slope 2

slope 2 = $\frac{9 - 5}{1 - 0}$

slope 2 = $\frac{4}{1}$

slope 2 = 4

3.- Compare the slope

slope 1 = 4 and slope 2 = 4, both slope are equals, then the lines are parallel.

8 0

3 years ago

Evaluate this exponential expression. 3 • (5 + 4)2 – 42 = A. 345 B. 15 C. 227 D. 46

LUCKY_DIMON [66]

The answer is C. 227

5 0

3 years ago

Given f(x)-x-5,solvr for x when f (x)=4

malfutka [58]

Answer:

-1-x

Step-by-step explanation:

i think im not sure

6 0

3 years ago

Mrs. Noyes fills up a 5 gallon can of gas from the McIntosh’s local convenience store. They are selling gas at $2.099 a gallon.

Tom [10]

<span>Mrs. Noyes fills up a 5 gallon can of gas from the McIntosh’s local convenience store. They are selling gas at $2.099 a gallon. How much is she going to pay at the pumpp</span>

5 0

3 years ago

The vertices of xyz are x (1,-4)

dexar [7]

Answer:

5. The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

6. The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

Step-by-step explanation:

If the point (x, y) translated by T → (h, k), then its image is (x + h, y + k)

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (-4, -3)

∴ h = -4 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + -4, -4 + -3)

∴ X' = (-3, -7)

∵ Y' = (-2 + -4, -1 + -3)

∴ Y' = (-6, -4)

∵ Z' = (3 + -4, 1 + -3)

∴ Z' = (-1, -2)

∴ The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (5, -3)

∴ h = 5 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + 5, -4 + -3)

∴ X' = (6, -7)

∵ Y' = (-2 + 5, -1 + -3)

∴ Y' = (3, -4)

∵ Z' = (3 + 5, 1 + -3)

∴ Z' = (8, -2)

∴ The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

6 0

3 years ago