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bazaltina [42]
3 years ago
9

Help with these two exercises please show work for both

Mathematics
2 answers:
max2010maxim [7]3 years ago
8 0
1) Divide the large shape into smaller rectangles, then find the area of each of the small rectangles and add them together. There are three rectangles (see image), let's call them A, B, and C. Use the equation: A=lw where A = area, l=length, w=width.

The area of A = 14*3 = 42 ft^{2}.
The area of B = (10+14)*8 = 192 ft^{2}.
The area of C = 5*17 = 85 ft^{2}.

Add these three areas together. Total area of shape = 42+192+85 = 319 ft^{2}.

B) To find the area of the shaded portion, you must find the area of the larger rectangle and subtract the area of the smaller rectangle from it. 

The area of the large rectangle is 22*40 = 880 ft^{2}.
The area of the small rectangle is 16*34 = 544 ft^{2}.

Subtract the small rectangle from the large one: 880-544 = 336 ft^{2}.

Soloha48 [4]3 years ago
3 0
1) (8x10)+(11x14)+(5x17)=319

2) area of big rectangle-area of small rectangle
(22x40)-(16x34)=336ft^2
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Step-by-step explanation:

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3 years ago
How do I write the sum of 6x and 2x is at least 39 ?
tatiyna
<h2>Put x = \dfrac{39}{8} I write the sum of 6x and 2x is at least 39 .</h2>

Step-by-step explanation:

We have,,

6x and 2x

To find, the value of x = ?

According to question,

The sum of 6x and 2x is at least 39

∴ 6x + 2x = 39

⇒ 8x = 39

⇒  x = \dfrac{39}{8}

∴ The value of x = \dfrac{39}{8}

Thus, put x = \dfrac{39}{8} I write the sum of 6x and 2x is at least 39 .

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Suppose you have $10 and your brother has $54. If you decide to save $10 of your allowance each week and your brother decides to
abruzzese [7]

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4 0
3 years ago
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If "-3(y-10=9" what is the value of y-12
zvonat [6]

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Solve the system. -3x-y=10; y-4z=-13; x-4y+z=4
kvasek [131]

9514 1404 393

Answer:

  (x, y, z) = (-3, -1, 3)

Step-by-step explanation:

Many graphing calculators can solve matrix equations handily. Here, we use a combination of methods.

Use the last equation to write an expression for z.

  z = 4 -x +4y

Substitute this into the second equation:

  y -4(4 -x +4y) = -13

  y -16 +4x -16y = -13

  4x -15y -3 = 0

In genera form, the first equation can be written as ...

  3x +y +10 = 0

Now, the solution to these two equations can be found to be ...

  x = (-15(10) -1(-3))/(4(1) -3(-15)) = (-150 +3)/(4+45) = -3 . . . using "Cramer's rule"

  y = -(10 +3x) = -(10 -9) = -1 . . . . from the first equation

  z = 4 -(-3) +4(-1) = 3 . . . . . . . . from our equation for z

The solution to the system is (x, y, z) = (-3, -1, 3).

_____

<em>Additional comment</em>

Written as an augmented matrix, the system of equations is ...

  \left[\begin{array}{ccc|c}-3&-1&0&10\\0&1&-4&-13\\1&-4&1&4\end{array}\right]

4 0
3 years ago
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