Answer:
- (b +4)(b +9)
- (c -5)(c +9)
- (k +2)(k +3)
Step-by-step explanation:
Consider the product ...
(x +a)(x +b) = x^2 +(a+b)x +ab
You will notice that the linear term (a+b)x has a coefficient (a+b) that is the sum of the factors of the constant term (ab).
For problems like this, it is useful to be able to factor the constant term, so you can choose the factors with the appropriate sum.
Signs are important. If the constant is positive, its factors will have the same sign, both positive or both negative. If the constant is negative, its factors will have opposite signs.
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1. b^2 +13b +36
Factors of 36 are ...
36 = 1·36 = 2·18 = 3·12 = 4·9 = 6·6
The sums of these are 37, 20, 15, 13, and 12. So, the factor pair we're looking for is 4 and 9. The factorization is ...
= (b +4)(b +9)
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2. c^2 +4c -45
The middle term is positive, so the larger magnitude factor will be positive. Factors of -45 are ...
-45 = -1·45 = -3·15 = -5·9
Sums of these factors are 44, 12, 4. So, the factor pair we're looking for is -5 and 9. The factorization is ...
= (c -5)(c +9)
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3. k^2 +5k +6
6 = 1·6 = 2·3 . . . . sums are 7 and 5 ⇒ factors of interest are 2 and 3
= (k +2)(k +3)
Answer:
y=7x - 2
Step-by-step explanation:
Slope- intercept form is - y=mx+b
In this equation, you would start off by isolating y.
So, you would move 7x to the right side like so-
7x -y =2
-7x -7x
Now you have
-y= -7x +2
Next step is to divide all number by -1 since you have -1y
-y=-7x+2
/-1 /-1 /-1
Now you have
y = 7x -2
Answer:
x=0
Step-by-step explanation:
all falls or passes through the x eventually
Answer:
10 k cal
Step-by-step explanation:
the ecosystem has ecological of 10%
the producer level is 1000 kilo-calories
the primary consumer will contain 10 % of the producer:
10000*10%=1000
the secondary consumer will contain 10% of the primary:
1000*10%=100 k cal
the tertiary will get 10% of the secondary: 100*10%=10 kcal
Answer:
420.9
Step-by-step explanation:
420.86827 ≈ 420.9 because we need to round to one decimal place.
Since 6 is greater than 5, we round 8 up to make it 9
420.9
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