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lana [24]
2 years ago
6

Suppose that 16-ounce bags of chocolate chip cookies are produced with weights that follow a normal distribution with mean weigh

t 16.1 ounces and standard deviation 0.1 ounce. for the distribution, approximately what percent of the bags will likely be underweight (that is, less than 16 ounces)?
Mathematics
1 answer:
AysviL [449]2 years ago
7 0

To solve this we use the z statistic. The formula for z score is:

z = (x – u) / s

where x is the sample value = less than 16, u is the sample mean = 16.1, s is standard dev = 0.1

 

z = (16 – 16.1) / 0.1

z = - 1

 

From the standard distribution tables at z = - 1,

P (z = -1) = 0.1587

 

<span>So about 15.87% is underweight.</span>

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Step-by-step explanation:

7^8*7=

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C. (7^3)^3= 343^3= 40353607  <------ right answer

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2 years ago
Jesse is playing a game with a number cube with faces numbered 1 through 6. What is the probability of rolling a number that is
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Answer:

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Step-by-step explanation:

The total possible  outcomes of cube = { 1, 2, 3 , 4 , 5 , 6}

Now, let E: Event of getting an even number and a multiple of 3

So, out of all the outcomes, {6) is the ONLY possible favorable outcome.

\textrm{P(E)}  =\frac{\textrm{Number of favorable outcomes }}{\textrm{Total number of outcomes}}

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8 0
3 years ago
The roosevelt middle school band is having a fundraiser. They sold a total of 300 hotdogs and hamburgers. Hot dogs were sold for
STALIN [3.7K]

Answer:

180 hamburgers

120 hotdogs

Step-by-step explanation:

In this question, we are asked to calculate the number of hamburgers and hotdogs sold by a company given the amount made by them and the total number of these snacks sold

We proceed as follows;

Let the amount of hotdogs sold be x and the amount of hamburgers sold be y.

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x + y = 300 ..........(I)

Now let’s look at the prices.

x number of hotdogs sold at $2, this give a total of $2x hotdogs

y number of hamburgers sold at $3, this give a total of $3y.

Adding both to give total, we have ;

2x + 3y = 780.......(ii)

This means we have two equations to solve simultaneously. From equation 1, we can say x = 300 -y

Now let’s insert this in the second equation;

2(300-y) + 3y = 780

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y = 780-600 = 180

Recall; x + y = 300

x = 300 -y

x = 300-180 = 120

5 0
2 years ago
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