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Ivenika [448]
2 years ago
10

Two more than the quotient of a number and 4 equals 7.

Mathematics
1 answer:
lara31 [8.8K]2 years ago
8 0

Answer:

20

Step-by-step explanation:

we can set up the equation like this:

n/4 + 2 = 7

subtract 2 from both sides

n/4 = 5

multiply 4 to both sides and you get...

n = 20

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A cheetah can run 70 mph. What is this speed in feet per hour
Rasek [7]
To answer this question you have to determine how many feet are in a mile and multiply it by 70. There are 5280 feet in a mile, so 5280 x 70= 369600. So he can run 369600ft in an hour. (im pretty sure lol, i feel like i may have misunderstood this question, are there any answer choices?)
8 0
3 years ago
Ellie drives 22.5 miles in 45 minutes. If she drove three hours in total at the same rate, how far did she go?
Scilla [17]

Answer:

Ellie drove 90 miles in three hours.

Step-by-step explanation:

6 0
2 years ago
How would I find all real solutions in x^4/3 -10^2/3 +21= 0
Oxana [17]

Answer:

Step-by-step explanation:

This equation looks complicated.We have to make it easier

let's say x^2/3 = t  and  x^4/3 = t^2

     

      t^2-10t+21=0   [ we can factorize this equation as a (t-3)(t-7) ]

     

      (t-3)(t-7)=0  [ that means , t can be 3 or 7 ]

But don't forget we have to find x not t so,

   t=x^2/3=3     ∛ x^2 = 3       x^2 = 9    x=3 or x= -3

  t=x^2/3=7      ∛x^2 = 7        x^2 = 343    x ~18.5  or x ~ -18.5

7 0
2 years ago
Anyone know what the answer is? I'd appreciate it if someone could help because im stuck
andrew-mc [135]

Answer:

100

Step-by-step explanation:

Isosceles triangle have 2 equal angles. Therefore the second angle in the triangle will also be 25.

Since the sum of angles in a triangle is 180.

180-(25x2) will give you the last angle in one of the triangles.

The other angle is identical so the angle at the top of the other triangle will also be 130.

The sum of angles in a circle is 360.

Therefore, angle x = 360-(130x2)

X= 100

7 0
3 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
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