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erastovalidia [21]
2 years ago
9

A circular mirror has a diameter of 30 inches and has a frame that is 3 inches thick. What is the circumference of the outer edg

e of the frame? Use 3.14 for π
π
. Round to the nearest inch.


19 inches
113 inches
104 inches
94 inches
Mathematics
2 answers:
g100num [7]2 years ago
6 0

By definition, the circumference of a circle is given by:


C=2πr


Where,


r: radius of the circle.


We have then, that the radius of the outer circle is given by:

r=15+3

r=18


Then, replacing values we have:

c=2(3.14)(18)


Answer:


The circumference of the outer edge of the frame is:  113 inches


option B



MaRussiya [10]2 years ago
6 0

<u>Answer:</u>

113 inches

<u>Step-by-step explanation:</u>

Diameter of a circular mirror = 30 inches

The frame is 3 inches thick so the diameter of the circular mirror with the frame at each side will be 30 + 3 + 3 = 36 inches

Therefore, its radius will be 36/2 = 18 inches

We know the formula for the circumference of a circle:

<em>Circumference = 2\pi r</em>

So putting the value of the radius in this formula to get:

Circumference = 2 x 22/7 x 18 = 113 inches

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Length of the side = 9 cm

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Solution:

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In square all sides are equal.

Area of the square = side × side

Side × side = 81

Side² = 9²    (∵81 = 9²)

Taking square root on both sides, we get

Side = 9 cm

Length of the side = 9 cm

To find the length of the diagonal:

In square all the angles are right angle.

Diagonal splits the square into two right angle triangle.

Using Pythagoras theorem,

<em>In right triangle, square of the hypotenuse is equal to the sum of the square of the other two sides.</em>

Here, diagonal is the hypotenuse.

\text{Diagonal}^2=9^2+9^2

\text{Diagonal}^2=81+81

\text{Diagonal}^2=2\times 81

Taking square root on both side,

Diagonal = 9\sqrt{2} cm

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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