Va rog mult sa ma ajutati ,imi trebuie neaparat . plz
1 answer:
You might be interested in
Answer:
g(t) = 10000(0.938)^t
Step-by-step explanation:
Given data:
car worth is $10,000 in 2012
car worth is $8000 in 2014
let linear function is given as
P(t) = at + b
which denote the value of car in year t
take t =0 for year 2012
at t =0, 10,000 = 0 + b
we get b = 10,000
take t =2 for year 2014
at t =2, P(2) = 2a + b
8800 = 2a + 10,000
a = - 600
Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000
let the exponential function where t denote t = 0 at 2012
putting t = 0 P(0) = 10,000 we get 10,000 = ab^0
a = 10,000
putting t = 2 p = 8800
b = 0.938
g(t) = 10000(0.938)^t
Answer:
The function that models the scenario is given as follows;
Step-by-step explanation:
The table of values are presented as follows;
The number of days, t, since the rumor started: 0, 1, 2, 3, 4, 5
The number of people, P, hearing the rumor: 10, 16, 26, 42, 66, 100
Imputing the given functions from the options into Microsoft Excel, and
solving using the given values of the variable, t, we have;
P t A B C D
10 0
10
10
10
10
16 1
16.07021 16.27604 16.34583
16.38095
26 2
25.43466 26.2797 26.574 26.72363
42 3
39.33834 41.89929 42.82868 43.30901
66 4
58.85058 65.51853 68.09014 69.45316
100 5
84.17395 99.55866 106.0177 109.5721
Therefore, by comparison, the function represented by most accurately models the scenario.