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zloy xaker [14]
3 years ago
7

Va rog mult sa ma ajutati ,imi trebuie neaparat . plz

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

amenda. de ce ai nevoie?

Step-by-step explanation:

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You throw two four-sided dice. Let the random variable X represent the maximum value of the two dice. Compute E(X). Round your a
Troyanec [42]

Answer:

E(X)=3.125

Step-by-step explanation:

We are given that two four sided dice.

Then , the sample space

{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}

Total number of outcomes=16

Let the random variable X represent the maximum value of the two dice

Outcomes                            X                                 P(X)

(1,1)                                          1                                 1/16

(1,2),(2,1),(2,2)                                   2                        3/16

(1,3),(2,3),(3,1),(3,2),(3,3)                    3                           5/16  

(1,4),(3,4) ,(2,4),(4,1),(4,2),(4,3),(4,4)    4                            7/16

Using the probability formula

P(E)=\frac{Favorable\;outcomes}{Total\;number\;of\;outcomes}

Now,

E(X)=\sum_{i=1}^{n}x_iP(x_i)

E(x)=1(1/16)+2(3/16)+3(5/16)+4(7/16)

E(x)=\frac{1+6+15+28}{16}

E(x)=\frac{50}{16}=3.125

7 0
3 years ago
Given AQRS-AXYZ, what is the value of tan(Q)?<br><br> A) 3/5<br> B) 3/4<br> C) 4/5<br> D) 4/3
iren [92.7K]

The answer is B.

Since ΔQRS ~ ΔXYZ, the value of tan(Q) is :

  • ∠Q = ∠X
  • tan(Q) = tan(X)
  • tan(X) = 3/4
  • tan(Q) = 3/4
3 0
2 years ago
Bartholemew will draw with replacement 160 tickets at random from a box with five tickets [0, 0, 0, 1, 2]. Estimate the chance t
cupoosta [38]

Answer:

0.0786

Step-by-step explanation:

It is given that Bartholemew had drawn the replacement of 160 tickets.

There are five tickets = [0, 0, 0, 1, 2]

Now we need to find the estimate of the ticket that has 1 on it and it turns up on the 32 draws exactly.

Since the probability of the drawing 1 out of 5 tickets is given by,   $\frac{1}{5} = 0.2$

So the binomial with the parameter of n = 160 and p = 0.2, we get

P (it turns up on exactly 32 draws) = P(X = 32)

Therefore,

$C(160, 32)\times (0.2)^{32}\times (0.8)^{160-32}$

= 0.0786

4 0
3 years ago
What's the common difference of the following arithmetic sequence?
Firlakuza [10]

Answer:

Step-by-step explanation:

6

Take the higher number and subtract the next lower value. It will tell you the difference.

17-11=6

7 0
4 years ago
Read 2 more answers
I really need help on this question. Can someone please help me with it???
Firlakuza [10]
The formula is y=mx+4 but I forgot how to do it
7 0
3 years ago
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