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zhenek [66]
3 years ago
7

What is the value of the product (3-2i)(3+2i)? 5 9+ 41 9-41 13

Mathematics
1 answer:
Paha777 [63]3 years ago
5 0

Answer:

13

Step-by-step explanation:

The given expression is (3-2i)(3-2i)

This is of the form (a-b)(a+b)

This is equivalent to \[a^{2}-b^{2}\], where a = 3 and b=2i

= \[3^{2}-(2i)^{2}\]

= \[9-4i^{2}\]

But \[i^{2} = -1\]

= \[9-4*(-1)\]

= \[9+4\]

= \[13\]

Hence the value of the expression (3-2i)(3-2i)  is 13.

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The percentage discount will be 9%.

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Answer:

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