Question

What is the value of the product (3-2i)(3+2i)? 5 9+ 41 9-41 13

Answer 1

Answer:

13

Step-by-step explanation:

The given expression is (3-2i)(3-2i)

This is of the form (a-b)(a+b)

This is equivalent to $\[a^{2}-b^{2}\]$, where a = 3 and b=2i

= $\[3^{2}-(2i)^{2}\]$

= $\[9-4i^{2}\]$

But $\[i^{2} = -1\]$

= $\[9-4*(-1)\]$

= $\[9+4\]$

= $\[13\]$

Hence the value of the expression (3-2i)(3-2i)  is 13.