Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
47.25 + 23.75 = 71
Step-by-step explanation:
Answer:
(0,3)
Step-by-step explanation:
Step 1: 7x-2y=-6 Step 2: 7x-2y=-6 solve by elimination of the y value
2(8x+y=3)2 +(16x+2y=6)
Step 3: 23x=0, which means <u>x=0</u>
Step 4: subtitute 0 into the equation 8x+y=3
you get 8(0)+y=3, which comes to 0+y=3
you get <u>y=3</u>
therefore the solution to this system is (0,3)
Answer:
so u wanna date ;)
Step-by-step explanation: