Is 0.90090009 an irrational number

Room temperature is considered to be 70 Fahrenheit. suppose the temperature is 23 Celsius. Is this greater than or less than roo

Thepotemich [5.8K]

Yes its actually 73.4 degrees Fahrenheit

7 0

2 years ago

8. By one estimate, 3% of all Siberian Husky puppies are born with two different

suter [353]

Answer:

C

Step-by-step explanation:

Mux= np

sigmax= $\sqrt{np(1-p)\\$

Mean = 50(.65)

Standard Deviation = $\sqrt{1.5(1-.03)}$

8 0

3 years ago

In one town 44% of all voters are Democrats if two voters are randomly selected for a survey find the probability that they are

kenny6666 [7]

Answer:

0.194

Step-by-step explanation:

Probability that BOTH are democrats means probability of <u>"one being democrat"</u> AND <u>"another also being democrat"</u>.

The AND means we need to MULTIPLY the individual probability of a person being democrat.

Probability that a voter is democrat is 44% (0.44) -- stated in the problem

Now, Probability BOTH being Democrats is simply MULTIPLYING 0.44 with 0.44

$0.44*0.44=0.1936$

Rounded to nearest thousandth, 0.194

Last answer choice is correct.

6 0

2 years ago

Find the first four terms of the sequence given by the following an=57-4(n-1),n=1,2,3

Crazy boy [7]

Answer:

57, 53, 49, 45

Step-by-step explanation:

Substitute for the n for n=1,2,3,4 so the first term is 57-4(1-1) so =57-4(0) so

a(1) = 57-0 = 57 so that is the 1st term

2nd term 57-4(2-1) so =57-4(1) so a(2) = 57-4 = 53, etc.

4 0

2 years ago

A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are

IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5 percent of these are defective.

This means that $p = 0.05$

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025$

0.0025 = 0.25% probability that both are defective

4 0

2 years ago