Question

Find center and radius (x-3)^2+y^2=8

Answer 1

Answer:

Center: (3, 0)

Radius: 2√2

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the equation:

$(x-3)^2+y^2=8\to(x-3)^2+(y-0)^2=(\sqrt8)^2$

Therefore

the center: $(3,\ 0)$

the radius: $r=\sqrt8\to r=\sqrt{4\cdot2}\to r=\sqrt4\cdot\sqrt2\to r=2\sqrt2$