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3 years ago

People with anorexia nervosa are often treated in a hospital because _____.

Chemistry

2 answers:

shutvik [7]3 years ago

8 0

<h3>Answer:</h3><h2>They have chemical imbalance.</h2><h3>Explanation: </h3>

Anorexia nervosa often referred to simply as anorexia, is an eating dysfunction defined by low weight, the anxiety of increasing weight, and a great hope to be thin, occurring in food limitation. Several people with anorexia perceive themselves as overweight even though in actual they are underweight.

Molodets [167]3 years ago

5 0

They have a chemical imbalance

Remember Anorexia is an eating disorder that causes people to obsess about weight and what they eat. It can get really serious.

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1) A certain compound has an empirical formula of CH_6O_ 2. Its molar mass is between 285 and 315 g/mol. What is its molecular f

KIM [24]

1. The molecular formula of the compound is C₆H₃₆O₁₂

2. The molecular formula of the compound is N₂H₄O₂

3 The empirical formula and molecular formula of the compound are: C₂H₃ and C₄H₆

4. The empirical formula of the compound is C₃H₆O

5. The empirical formula of the compound is ZrSiO₄

<h3>1. How to determine the molecular formula </h3>

Empirical formula = CH₆O₂
Molar mass = (285 + 315) / 2 = 600 / 2 = 300 g/mole
Molecular formula =?

Molecular formula = empirical × n = molar mass

[CH₆O₂]ₙ = 300

[12 + (6×1) + (16×2)]ₙ = 300

50n = 300

Divide both side by 74

n = 300 / 50

n = 6

Molecular formula = [CH₆O₂]ₙ

Molecular formula = [CH₆O₂]₆

Molecular formula = C₆H₃₆O₁₂

<h3>2. How to determine the molecular formula </h3>

Empirical formula = NH₂O
Molar mass = (55 + 65) / 2 = 120 / 2 = 60 g/mole
Molecular formula =?

Molecular formula = empirical × n = molar mass

[NH₂O]ₙ = 60

[14 + (2×1) + 16]ₙ = 60

32n = 60

Divide both side by 32

n = 60 / 32

n = 2

Molecular formula = [NH₂O]ₙ

Molecular formula = [NH₂O]₂

Molecular formula = N₂H₄O₂

<h3>3. How to determine the empirical formula and molecular formula</h3>

We'll begin by obtaining the empirical formula. This is illustrated below:

Carbon (C) = 88.9%
Hydrogen (H) = 11.1%
Empirical formula =?

Divide by their molar mass

C = 88.9 / 12 = 7.4

H = 11.1 / 1 = 11.1

Divide by the smallest

C = 7.4 / 7.4 = 1

H = 11.1 / 7.4 = 3/2

Multiply by 2 to express in whole number

C = 1 × 2 = 2

H = 3/2 × 2 = 3

Thus, the empirical formula of the compound is C₂H₃

Finally, we shall determine the molecular formula of the compound. This is illustrated below:

Molar mass of compound = 54 g/mol
Empirical formula = C₂H₃
Molecular formula =?

Molecular formula = empirical × n = molar mass

[C₂H₃]ₙ = 75.16

[(12×2) + (3×1)]ₙ = 54

27n = 54

Divide both side by 27

n = 54 / 27

n = 2

Molecular formula = [C₂H₃]ₙ

Molecular formula = [C₂H₃]₂

Molecular formula = C₄H₆

<h3>4. How to determine the empirical formula</h3>

Carbon (C) = 62.07%
Hydrogen (H) = 10.34%
Oxygen (O) = 27.59%
Empirical formula =?

Divide by their molar mass

C = 62.07 / 12 = 5.1725

H = 10.34 / 1 = 10.34

O = 27.59 / 16 = 1.724

Divide by the smallest

C = 5.1725 / 1.724 = 3

H = 10.34 / 1.724 = 6

O = 1.724 / 1.724 = 1

Thus, the empirical formula of the compound is C₃H₆O

<h3>5. How to determine the empirical formula</h3>

Zr = 49.76%
Si = 15.32%
O = 34.91%
Empirical formula =?

Divide by their molar mass

Zr = 49.76 / 91 = 0.547

Si = 15.32 / 28 = 0.547

O = 34.91 / 16 = 2.182

Divide by the smallest

Zr = 0.547 / 0.547 = 1

Si = 0.547 / 0.547 = 1

O = 2.182 / 0.547 = 4

Thus, the empirical formula of the compound is ZrSiO₄

Learn more about empirical and molecular formula:

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7 0

2 years ago

4. How many atoms are contained in 3.55 moles of sodium chloride?

DochEvi [55]

Hey there!

There are 6.022 x 10²³ particles in 1 mole.

We have 3.55 moles.

6.022 x 10²³ x 3.55

2.14 x 10²⁴

This is how many particles we have.

NaCl has 2 atoms for every unit.

So we multiply this by 2.

2 x 2.14 x 10²⁴ = 4.28 x 10²⁴

There are 4.28 x 10²⁴ atoms in 3.55 moles of sodium chloride.

Hope this helps!

5 0

4 years ago

Read 2 more answers

WILL GIVE BRAINIEST

Tems11 [23]

Answer:3/12

Explanation:

4 0

2 years ago

Which statement about melting and boiling points is true? Question 3 options:

bonufazy [111]

Answer:

Explanation:

I believe it is B but I am not entirely sure! don't do this is B doesn't sound or look right to you!

4 0

3 years ago

How many grams of C6H6O3 will react with 97.0grams of O2?<br><br> C6H6O3+3O2 ===> 6CO+3H2O

likoan [24]

Answer:

127.3 g

Explanation:

Data Given

mass of O₂= 97 g

mass of C₆H₆O₃ = ?

Reaction Given:

C₆H₆O₃ + 3O₂ --------> 6CO + 3H₂O

Solution:

First find the mass of C₆H₆O₃ from the reaction that it combine with how many grams of oxygen (O₂).

Look at the balanced reaction

C₆H₆O₃ + 3O₂ --------> 6CO + 3H₂O

1 mol 3 mol

So 1 mole of C₆H₆O₃ combine with 3 moles of O₂

Now

convert the moles into mass for which we have to know molar mass of C₆H₆O₃ and O₂

Molar mass of C₆H₆O₃

Molar mass of C₆H₆O₃ = 6(12) + 6(1) +3(16) = 72 + 6 + 48

Molar mass of C₆H₆O₃ = 126 g/mol

mass of C₆H₆O₃

mass in grams = no. of moles x molar mass

mass of C₆H₆O₃ = 1 mol x 126 g/mol

mass of C₆H₆O₃ = 126 g

Molar mass of O₂ = 2(16)

Molar mass of O₂= 32 g/mol

mass of O₂

mass in grams = no. of moles x molar mass

mass of O₂ = 3 mol x 32 g/mol

mass of O₂ = 96 g

So,

96 g of O₂ combine with 126 g of C₆H₆O₃ then how many grams of C₆H₆O₃ will combine with 97.0grams of O2

Apply unity Formula

96 g of O₂ ≅ 126 g of C₆H₆O₃

97 g of O₂ ≅ X g of C₆H₆O₃

By cross multiplication

X g of O₂ = 126 g x 97 g / 96 g

X g of O₂ = 127.3 g

127.3 g of C₆H₆O₃ will combine with 97 g of O₂

mass of C₆H₆O = 127.3 g

7 0

3 years ago