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3 years ago

People with anorexia nervosa are often treated in a hospital because _____.

Chemistry

2 answers:

shutvik [7]3 years ago

8 0

<h3>Answer:</h3><h2>They have chemical imbalance.</h2><h3>Explanation: </h3>

Anorexia nervosa often referred to simply as anorexia, is an eating dysfunction defined by low weight, the anxiety of increasing weight, and a great hope to be thin, occurring in food limitation. Several people with anorexia perceive themselves as overweight even though in actual they are underweight.

Molodets [167]3 years ago

5 0

They have a chemical imbalance

Remember Anorexia is an eating disorder that causes people to obsess about weight and what they eat. It can get really serious.

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GUYS I REALLY NEED THIS ASAP!!!!!

Nastasia [14]

Answer:

I don't think so

Explanation:

The equation doesn't look balanced

8 0

3 years ago

A diploid somatic ("body") cell has 2n = 20 chromosomes. At the end of mitosis, each daughter cell would have ______ chromosomes

kozerog [31]

Answer:

At the end of mitosis, 2n = 20

At the end of meiosis I, n = 10

At the end of meiosis II, n = 10

Explanation:

Mitosis is a type of cell division in which daughter cell produced are genetically identical to their mother cell. So, no. of chromosome does not change after mitosis.

So, at the end of mitosis, each daughter cell would have <u>20</u> chromosome.

Meiosis is a type of cell division in which mother cell produces two haploid cells ones with a single set of chromosomes.

Meiosis is a two step cell division, Meiosis I and Meiosis II.

In meiosis I, homologous pair separates, so no. of chromosomes becomes half.

In meiosis II, sister chromatids separates. So, the number of chromosomes remains same (i.e. Have same no. of chromosome as present in cell produced after meiosis I).

So, at the end of mitosis, each daughter cell would have <u>20</u> chromosome.

At the end of meiosis I, each daughter cell would have n = 10 chromosomes. At the end of meiosis II, each daughter cell would have n = 10 chromosomes.

7 0

3 years ago

2 NaCL + CaO = CaCL2 + Na2O

Naily [24]

222 grams of calcium chloride is produced.

<h3><u>Explanation</u>:</h3>

The mole concept and the chemical equation are very much closely related with each other. In the chemical reaction, the compounds or elements in both sides are balanced according to the number of atoms of each side of the reaction. So from there we can easily find the amount of reactant reacts to produce desired product.

Here we can see that 2 moles of sodium chloride produces 1 mole of calcium chloride.

So, 4 moles of sodium chloride will produce 2 moles of calcium chloride.

Now, atomic weight of calcium =40.

Atomic weight of chlorine =35.5.

So,the molecular weight of calcium chloride = $40+ 35.5\times2$

=111.

It means, 1 mole of calcium chloride weighs 111 grams.

So 2 moles of calcium chloride weighs $111\times2$ grams = 222 grams.

7 0

4 years ago

The percentage of keys you type correctly is A. accuracy B. correctness C. exactness D. precision WHO EVER GETS THIS EARNS BRAIN

e-lub [12.9K]

The answer is A: accuracy

5 0

2 years ago

NEED HELP ASAP NOT DIFFICULT

Burka [1]

Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

5 0

3 years ago

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