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Svetradugi [14.3K]
3 years ago
11

The radius of a uranium atom is 149 pm. How many uranium atoms would have to be laid side by side to span a distance of 4.96 mm?

Chemistry
2 answers:
nikitadnepr [17]3 years ago
4 0

Answer:

4960000000 pm

Explanation:

4.96*1000000000= 4960000000

djverab [1.8K]3 years ago
3 0

Answer:

Uranium atoms required to be laid side by side to span a distance of 4.96 mm is 1.6644\times 10^7 atoms.

Explanation:

The radius of a uranium atom ,r = 149 pm =1.49\times 10^{-7} mm

1 pm=10^{-9} mm

The diameter of a uranium atom ,d =

d = 2r =2\times 1.49\times 10^{-7} mm=2.98\times 10^{-7} mm

The let the uranium atom to be laid side by side to span a distance of 4.96 mm be x.

x\times d=4.96 mm

x=\frac{4.96 mm}{d}=\frac{4.96 mm}{2.98\times 10^{-7} mm}=1.6644\times 10^7 atoms.

Uranium atoms required to be laid side by side to span a distance of 4.96 mm is 1.6644\times 10^7 atoms.

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Answer:

The answer to your question is    Final volume = 58.37 ml

Explanation:

Data

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Process

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Simplification

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