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Harman [31]
3 years ago
7

Give the equation of the line through the point ( - 10,9) with a slope of -1/5

Mathematics
1 answer:
hichkok12 [17]3 years ago
7 0

Equation of the line in slope-intercept form is y = -1/5 x + 9

Step-by-step explanation:

  • Step 1: Given slope of the line is -1/5 and the point is (-10, 9). Here m=-1/5.

⇒ y = -1/5 x + b  ------ (1)

  • Step 2: Find the y-intercept of the line, b. Since the line passes through (-10, 9) substitute x = -10 and y = 9 in eq(1)

⇒ 9 = -1/5 × -10 + b = 2 + b

⇒ b = 9 - 2 = 7

  • Step 3: Slope intercept form of the line is y = mx + b. Form the equation using the values of m and b.

⇒ y = -1/5 x + 7

It can also be written as 5y + x = 35

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Use point-slope form to write the equation of a line that passes through the point
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Answer:

y - 8 = -2(x - 9)

Step-by-step explanation:

Given the slope, m = -2, and the point, (9, 8):

Let (x₁, y₁) = (9, 8)

slope (<em>m </em>) = -2

We can substitute these values into the following <u>point-slope form</u>:

y - y₁ = m(x - x₁)

y - 8 = -2(x - 9)  ⇒ This is the point-slope form.

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26.   2x^2 +4x -10 = 0       (-4 + - (root(4^2 - 4*2*-10)))/2*2   =  
(-4 + - (root(96)))/4
(-4 + (root(96)))/4  ≈  1.45
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27. f(x) = 0 when any of the components that multiply together equal 0 for this function therefore   x -2 = 0    x +3 = 0    x -5 = 0   so   f(x) = 0 when x = 2, -3 or 5 


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26 = 3x - 2 - 7x
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