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stira [4]
2 years ago
10

Horizontally compress the exponential function f(x)=2^x by a factor of 3

Mathematics
1 answer:
MakcuM [25]2 years ago
7 0

The horizontally compress the exponential function f(x)=2^x by a factor of 3 is f(3x)=2^3x

When we compress a function y=f(x) by a scale factor of 'k', where k >1, then the function after compression will become :

y=f(x), where k>1

We have given the Exponential function.

<h3>What is the scale factor?</h3>

The scale factor is a measure for similar figures, that look the same but have different scales or measures. Suppose, two circle looks similar but they could have varying radii. The scale factor states the scale by which a figure is bigger or smaller than the original figure.

The scale factor of the compression (k): 5

Then after horizontal compression, the exponential function will become

f(3x)=2^3x

To learn more about the exponential function visit:

brainly.com/question/12940982

#SPJ1

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Montrell saves 8% of each paycheck for his college fund. This week he saved $18.80 from his paycheck, how much was he paid?
castortr0y [4]
8% of x = $18.80
x = 18.80/8%
x = 18.80/0.08
x = $235
8 0
3 years ago
A glacier grew g feet over winter. It shrank 25 feet in summer.if the total change was -10 feet how much had the glacier grown i
Nataly [62]
You would have to add 25 and -10 together
5 0
3 years ago
The width of a rectangle is the length minus 2 units. the area of the rectangle is 35 units
Mariana [72]

Answer:

Length=7units\\\\Width=5units

Step-by-step explanation:

Width=(Length-2) units

W=(L-2) units

Area of the rectangle= 35 square units

Area = length* Width

35= L*(L-2)\\\\35=L^2-2L

Subtracting 35 both sides:

L^2-2L-35=0

Solving the quadratic equation for 'L' ;

Using factorization:

L^2+5L-7L-35=0

Taking common from the equation :

L(L+5)-7(L+5)=0\\\\(L+5)(L-7)=0\\\\L+5=0\\\\L=-5

OR

L-7=0\\\\L=7

The length cannot be negative, therefore Length(L)= 7

Width=Length-2\\\\=7-2\\\\=5 units

Length=7units\\\\Width=5units

8 0
3 years ago
A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th
Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let S(t) be the amount of sugar in the tank at time t. Then S(0)=25.

Sugar is added to the tank at a rate of <em>P</em> lb/min, and removed at a rate of

\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}

Separate variables, integrate, and solve for <em>S</em>.

\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt

\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt

-100\ln\left|P-\dfrac S{100}\right|=t+C

\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t

P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}

\dfrac S{100}=P-Ce^{-100t}

S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}

Use the initial value to solve for <em>C</em> :

S(0)=25\implies 25=100P-C\implies C=100P-25

\implies S(t)=100P-(100P-25)e^{-100t}

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick <em>P</em> such that

S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}

5 0
3 years ago
the food bill for meal at a restaurant is $12. THe sales tax is 6.5%, and you leave 15% tip. Wat is the total cost of the meal?
jeka57 [31]

Answer:

Step-by-step explanation:

12*6.5%=0.72

12+15%=13.8

0.72+13.8=14.52

6 0
2 years ago
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