Determine first the common ratio (r) of the geometric sequence by,
r = (t5 / t3)^(1/(5 - 3))
Substituting the known values from the given,
r = (3750 / 150)^(1/2) = 5
The sixth term may be obtained by multiplying the fifth term (t5 = 3750) by the common ratio. This is shown below,
t6 = (3750) x 5 = 18750
Thus, the 6th term of the geometric sequence is 18750.
Answer:
The answer is D. -9 and -3
Step-by-step explanation:
since the graph starts at 1 and goes backwards, it cant be 1. so that rules out A. and B. then it requires the numbers to be negative because if they are a whole number over 1, they don´t fit the inequality. I hope this helps :))
Answer:
17, 18
Step-by-step explanation:
closest perfect square that is lower than 307 is 289
closest perfect square that is greater than 307 is 324
![\sqrt{289} < \sqrt{307} < \sqrt{324}](https://tex.z-dn.net/?f=%5Csqrt%7B289%7D%20%3C%20%5Csqrt%7B307%7D%20%3C%20%5Csqrt%7B324%7D)
![17](https://tex.z-dn.net/?f=17%3C%5Csqrt%7B307%7D%20%3C18)
Answer:
Domain: all real numbers
Step-by-step explanation:
This graph is a parabola. It's equation looks like it should be:
y = x^2 - 1
If you have a graph and are looking for the domain, you are determining where the graph exists. For what x's the graph exists. If you have the equation then the domain is what x's may be put into the equation. There are no limitations on what numbers can go into this equation so the domain is all real numbers.
There are several ways to write the domain is all real numbers, set builder notation and interval notation. But the main idea is that it is all real numbers.
Part A:
Given that a<span> bag contains 10 white golf balls and 6 striped golf balls, the ratio of white to striped golf balls is 10 : 6 = 5 : 3.
Given that </span>a<span> golfer wants to add 122 golf balls to the bag, the of balls each he should add is given by:
![5\left( \frac{122}{5+3} \right) \ : \ 3\left( \frac{122}{5+3} \right)=5\left( \frac{122}{8} \right) \ : \ 3\left( \frac{122}{8} \right) \\ \\ =5(15.25) \ : \ 3(15.25)=76.25 \ : \ 45.75 \\ \\ \approx76:46](https://tex.z-dn.net/?f=5%5Cleft%28%20%5Cfrac%7B122%7D%7B5%2B3%7D%20%5Cright%29%20%5C%20%3A%20%5C%203%5Cleft%28%20%5Cfrac%7B122%7D%7B5%2B3%7D%20%5Cright%29%3D5%5Cleft%28%20%5Cfrac%7B122%7D%7B8%7D%20%5Cright%29%20%5C%20%3A%20%5C%203%5Cleft%28%20%5Cfrac%7B122%7D%7B8%7D%20%5Cright%29%20%5C%5C%20%20%5C%5C%20%3D5%2815.25%29%20%5C%20%3A%20%5C%203%2815.25%29%3D76.25%20%5C%20%3A%20%5C%2045.75%20%5C%5C%20%20%5C%5C%20%5Capprox76%3A46)
Therefore, the golfer shold add 76 white golf balls and 46 striped golf balls.
Part B.
You did not indicate the scale factor.
Assuming the scale factor is given by D(o, k) where k can be any number, then the cordinate of the </span><span>coordinates of the image of the quadrilateral VWXY are given by:
V'(6k, 2k), W(-2k,
4k), X(-3k, -2k), Y(3k,-5k)
That is you multiply the scale factor to the coordinates of the preimage to get the coordinates of the image.
</span>