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3 years ago

Please show work and help!!

Mathematics

2 answers:

grandymaker [24]3 years ago

4 0

A.25
Work:
-5x-5=25
Hope his helps.

Aleonysh [2.5K]3 years ago

3 0

A) 25

-5 • -5 = 25

Hope this helped!

Also, helpful tip! If the exponent is even then you can drop the negative sign in the answer.

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Find an equation of the line in the form whose x-intercept is 15 and y-intercept is 3, where a, b, and c are integers with n

madreJ [45]

x-intercept = (15, 0) y-intercept = (0, 3)

slope (m) = (y₂ - y₁)/(x₂ - x₁) = (0 - 3)/(15 - 0) = -3/15 = -1/5

Point-Slope formula: y - y₁ = m(x - x₁) ; where (x₁, y₁) is one of the given points

y - 0 = (-1/5)(x - 15)

-5y = x - 15

x + 5y = 15

Answer: x + 5y = 15

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3 years ago

If f(x)=2x^3+5√(x-2) complete the following statement, f(6)=

solong [7]

Answer: 442

Step-by-step explanation:

$f(x)=2x^3+5\sqrt{(x-2)}$

$f(6)$

Simply replace all the x's in the equation for 6

$f(6)=2(6)^3+5\sqrt{(6-2)}\\ f(6)=2(216)+5\sqrt{4}\\ f(6)=432+5*2\\f(6)=432+10\\f(6)=442$

5 0

3 years ago

A 10-pound block of ice melts at a rate of 3% per hour. Find the weight of the block of ice after 1 day.

mylen [45]

Answer:

The weight of the block of ice after 1 day is of 4.81 pounds.

Step-by-step explanation:

Equation for exponential decay:

The equation that models an amount after t hours, subject to exponential decay, is given by:

$A(t) = A(0)(1 - r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

A 10-pound block of ice melts at a rate of 3% per hour.

This means that $A(0) = 10, r = 0.03$

$A(t) = A(0)(1 - r)^t$

$A(t) = 10(1 - 0.03)^t$

$A(t) = 10(0.97)^t$

Find the weight of the block of ice after 1 day.

One day has 24 hours, so this is A(24).

$A(24) = 10(0.97)^{24} = 4.81$

The weight of the block of ice after 1 day is of 4.81 pounds.

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2 years ago

Please help me i need help pls

OverLord2011 [107]

Answer:

see explanation

Step-by-step explanation:

(b)

30n - 12 ( factor out the gcf 6 from each term )

= 6(5n - 2) ← in factored form

(c)

6x + 9y ( factor out the gcf 3 from each term )

= 3(2x + 3y) ← in factored form

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3 years ago

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amid [387]

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Step-by-step explanation:

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3 years ago

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