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JulijaS [17]
3 years ago
11

Which is the equation of the given line in point- slope form?

Mathematics
1 answer:
Alina [70]3 years ago
3 0

Answer:

y-0=-1(x-8)

Step-by-step explanation:

The given line passes through (0,8) and (8,0).

The slope of this line is m=\frac{8-0}{0-8} =-1.

The point-slope form is given by:

y-y_1=m(x-x_1)

We substitute the slope and the point (8,0) to get:

y-8=-1(x-0)

We substitute the slope and the point (0,8) to get:

y-0=-1(x-8)

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What is an equation of the line that passes through the point (-4,-6) and is perpendicular to the line 4x+5y=25
elixir [45]

Answer:

y =  \frac{5}{4} x - 1

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is its gradient and c is its y-intercept.

First rewrite the equation of the given line in the form of y=mx +c.

4x+5y=25

5y= -4x +25

y =  -  \frac{4}{5} x + 5

The gradient of the given line is -  \frac{4}{5}

The product of the gradient of perpendicular lines is -1.

( -  \frac{4}{5} )(gradient \: of \: line) =  - 1 \\ gradient \: of \: line =  - 1  \div ( -  \frac{4}{5} ) \\ gradient \: of \: line =  \frac{5}{4}

Thus, m= \frac{5}{4}

y =  \frac{5}{4} x + c

Substitute a coordinate to find c.

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