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Vedmedyk [2.9K]
3 years ago
14

Which expression is equivalent to 3sq 256x^10 y^7

Mathematics
2 answers:
kobusy [5.1K]3 years ago
6 0
Hold up I’m gonna help u
forsale [732]3 years ago
6 0

For this case we have the following expression:

\sqrt[3]{256x^{10}*y^{7}}

We can rewrite it in the following way:

\sqrt[3]{(64*4)x^{9+1}*y^{6}*y^{1}}

Simplifying, taking into account that: ax ^ b * ax ^ b = (a * a) x^{b+b}, we have the following:

4x^3*y^2(\sqrt[3]{4x*y} )

Thus, the simplified expression is given by:

4x^3*y^2(\sqrt[3]{4x*y} )

Answer:

4x^3*y^2(\sqrt[3]{4x*y} )


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Find the distance between -6 - 8
Viefleur [7K]

Answer:

2

Number line.

We start at -6 or -8.

If we start from -6, we will be going __ spaces to the left until we get to -8.

Or start from -8 and go __ spaces to the right until you get to -6.

Then count the spaces.

You'll get 2.

4 0
2 years ago
Read 2 more answers
When using the given diagram to determine the area of the pentagon by decomposition, which statements are correct?:
pogonyaev

Answer:

Options (B) and (E)

Step-by-step explanation:

Area of ΔABC = \frac{1}{2}(\text{Base})(\text{Height})

                        = \frac{1}{2}(14)(6)

                        = 42 in²

Area of trapezoid ADEC = \frac{1}{2}(b_1+b_2)h

[Here, b_1 and b_2 are the parallel sides and 'h' is the height of the isosceles trapezoid given]

= \frac{1}{2}(10+14)(8)

= 96 in²

Area of the pentagon = Area of triangle ABC + Area of trapezoid ADEC

                                    = 42 + 96

                                    = 138 in²

Therefore, Options (B) and (E) are the correct options.

6 0
2 years ago
Construct a 99% confidthence interval for the population mean .Assume the population has a normal distribution. A group of 19 ra
Kobotan [32]
<h2>Answer with explanation:</h2>

Confidence interval for mean, when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n= sample size

s= sample standard deviation

t_{\alpha/2} = Critical t-value for n-1 degrees of freedom

We assume the population has a normal distribution.

Given, n= 19 , s= 3.8 , \overline{x}=22.4

\alpha=1-0.99=0.01

A) Critical t value for \alpha/2=0.005 and degree of 18 freedom

t_{\alpha/2} = 2.8784

B) Required confidence interval:

22.4\pm ( 2.8744)\dfrac{3.8}{\sqrt{19}}\\\\=22.4\pm2.5058\\\\=(22.4-2.5058,\ 22.4+2.5058)=(19.8942,\ 24.9058)\approx(19.9,\ 24.9)

Lower bound = 19.9 years

Uppen bound = 24.9 years

C) Interpretation: We are 99% confident that the true population mean of lies in (19.9, 24.9) .

5 0
3 years ago
Jean’s statement is or isn’t and the median value of the data pounds
FrozenT [24]
The estimate of the mean  is reasonable beauase the median of the data is 26 lbs.
5 0
3 years ago
HELP ASAP<br> What is the area of this polygon on a coordinate plane?
iren2701 [21]

Answer:

Step-by-step explanation:

One way to find the area of any polygon is to find areas of all of its inside sections and then adding them together. For example, if I had a polygon made of a square stuck to a triangle, I could calculate the area of the polygon by adding the area of the square to the area of the triangle.

3 0
3 years ago
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