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kvv77 [185]
3 years ago
12

Answer Wednesday Thursday and Friday

Mathematics
2 answers:
dsp733 years ago
8 0
To be honest I actually have no clue
Jlenok [28]3 years ago
5 0
Monday Tuesday Wednesday Thursday Friday
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5 Vince draws the figures below. He says each figure has an area of 8 square units. Is he correct? Decide if each figure has an
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Answer:ok so it is 1 A 2C 3 F 4H

Step-by-step explanation:

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2 years ago
Plz help me with this
hichkok12 [17]

Answer:

8

Step-by-step explanation:

0.3{10} + 10 / 2

3 + 10/2

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Five members of the Varsity Math team are running late for a big
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F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
DerKrebs [107]

a. Parameterize C by

\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath

with 0\le t\le1.

b/c. The line integral of \vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath over C is

\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt

=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt

=\displaystyle10\int_0^1\mathrm dt=\boxed{10}

d. Notice that we can write the line integral as

\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

By Green's theorem, the line integral is equivalent to

\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy

where D is the triangle bounded by C, and this integral is simply twice the area of D. D is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0
3 years ago
1. Which figure comes next in the pattern below? ​
LenaWriter [7]
The awnser is D
Purrr
6 0
3 years ago
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