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mina [271]
3 years ago
10

Solve the system by substitution 4x+4y= 12 and x+2y=11

Mathematics
1 answer:
Reika [66]3 years ago
4 0

Answer:

x = -5 and y = 8

Step-by-step explanation:

To solve the system by substitution, solve one equation for a variable. Then substitute the equation into the other equation.

x + 2y = 11 becomes x = 11 - 2y

Substitute x = 11 -2y into 4x + 4y = 12.

4(11-2y) + 4y = 12

44 - 8y + 4y = 12

44 - 4y = 12

32 = 4y

y = 8

Substitute again with y = 8 into the equation to find x.

x = 11 - 2(8)

x = 11 - 16

x = -5

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Answer:

Dimensions: 0.4 by 3.2 by 1.2

Step-by-step explanation:

I'm assuming here that we are cutting out squares out of each of the metal's corners:

Let x = the length of each cut-out square,

Each base (of the desired net square folded) is 4-2x, and 2-2x respectively,

Volume = x(4-2x)(2-2x)

             = 4x^3 - 12x + 8x

Now we take the derivative:

\frac{d}{dx}\left[4x^3-12x^2+8x\right]\\\\= \frac{d}{dx}\left(4x^3\right)-\frac{d}{dx}\left(12x^2\right)+\frac{d}{dx}\left(8x\right)\\\\= 12x^2-24x+8

We equate to 0 (0 for max volume), and solve using the quadratic formula:

12x^2-24x+8=0,\\\\x_{1,\:2}=\frac{-\left(-24\right)\pm \sqrt{\left(-24\right)^2-4\cdot \:12\cdot \:8}}{2\cdot \:12}\\\\= \frac{-\left(-24\right)\pm \:8\sqrt{3}}{2\cdot \:12}\\\\\mathrm{Separate\:the\:solutions}:\\\\x_1=\frac{-\left(-24\right)+8\sqrt{3}}{2\cdot \:12},\:x_2=\frac{-\left(-24\right)-8\sqrt{3}}{2\cdot \:12}\\\\x =\frac{3+\sqrt{3}}{3},\:x=\frac{3-\sqrt{3}}{3}\\\\x=1.57735\dots ,\:x=0.42264\dots

So we approximate the side lengths to be 1.6 and 0.4 respectively. But when we plug in 1.6 for x, we get the volume as negative. Therefore x has to be 0.4.

Side lengths: 0.4, 4-2(0.4) => 3.2, 2-2(0.4) => 1.2

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