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3 years ago

What is the opposite of 5.25?

Mathematics

1 answer:

WARRIOR [948]3 years ago

7 0

Answer:

-5.25

Step-by-step explanation:

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Which number below is a perfect square? 100 90 50 75

Umnica [9.8K]

100

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3 years ago

Find the value of y, given value of x.

podryga [215]

Step-by-step explanation:

a. y = 2 + 4.3(-6)

y= 2- 25.8

y= -23.8 or y= -24

b. y= (9-3)2

18-6=12

c. y= 3.5-2

y= 1.5

d. y= 5(-2) - 4

y= -10-4

y= -14

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3 years ago

One number is 7 less than a second number. Twice the second number is 7 less than 5 times the first. Find the smaller of two num

aliya0001 [1]

N = x-7
2x = 5n-7

2x = 5(x-7)-7
2x=5x-35-7
-3x=-42
x=14
n=7

7 is the answer

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4 years ago

HELP 30 POINTS please in a hurry

eimsori [14]

To be a function every input value (x) can only have one output value (y)

On the graph there are 2 out put values for x = 2 so it is not a function.

The answer would be C.

8 0

3 years ago

Graph the functions on the same coordinate axis. {f(x)=−2x+1g(x)=x2−2x−3

NikAS [45]

Answer:

(2,-3) and (-2,5)

Step-by-step explanation:

Let us graph the two equations one by one.

1. $f(x)=-2x+1$

If we compare this equation with the slope intercept form of a line which is given as

$y=mx+c$

we see that m = -1 and c =1

Hence the slope of the line is -2 and the y intercept is 1. Hence one point through which it is passing is (0,1) .

Let us find another point by putting x = 1 and solving it for y

$y=-2(1)+1$

$y=-2+1 = -1$

Let us find another point by putting x = 2 and solving it for y

$y=-2(2)+1$

$y=-4+1 = -3$

Hence the another point will be (2,-3)

Let us find another point by putting x = -2 and solving it for y

$y=-2(-2)+1$

$y=+1 = 5$

Hence the another point will be (-2,5)

Now we have two points (0,1) ,(1,-1) , (2,-3) and (-2,5) we joint them on line to obtain our line

$g(x)=y=x^2-2x-3$

$y=x^2-2x+1-1-3$

$y=(x-1)^2-4$

$(y+4)=(x-1)^2$

It represents the parabola opening upward with vertices (1,-4)

Let us mark few coordinates so that we may graph the parabola.

i) x=0 ; $y=y=(0)^2-2(0)-3=0-0-3=-3$ ; (0,-3)

ii)x=-1 ; $y=(-1)^2-2(-1)-3=1+2-3=0$ ; (-1,0)

iii) x=2 ; $y=(2)^2-2(2)-3 = 4-4-3 =-3$ ;(2,-3)

iii) x=1 ; $y=(1)^2-2(1)-3 = 1-2-3 =-4$ ;(1,-4)

iii) x=-2 ; $y=(-2)^2-2(-2)-3 = 4+4-3 =5$ ;(-2,5)

Now we plot them on coordinate axis and line them to form our parabola

When we plot them we see that we have two coordinates (2,-3) and (-2,5) are common , on which our graphs are intersecting. These coordinates are solution to the two graphs.

3 0

4 years ago