Wrong those are considered complex numbers. pure imaginary numbers have ,0 for a and are thus in the form. 3i, -2i, 17i. etc
Answer: x=6
Y=6
Step-by-step explanation:
Using the elimination method
3x+5y=48.....equ1
-3x+5y=12......equ2
Add equation 1 &2
3x+5y=48
+
-3x+5y=12
Answer =
10y=60
Y=60/10
Y=6
Substitute for y in equation 1
3x+5y=48
3x+5(6)=48
3x+30=48
3x=48-30
3x=18
X=18/3
X=6
Therefore,
X= 6
Y= 6
4 < = x + 4 < = 8.....subtract 4 from all sections
4 - 4 < = x + 4 - 4 < = 8 - 4...simplify
0 < = x < = 4
this would produce a number line with a solid circle on 0 and a solid circle on 4, with shading in between....just like the graph shown in the picture u posted.
so the expression u would add would be : x + 4
Answer:
<h2>(-4,-2)</h2>
Step-by-step explanation:
(-4,-5)
move up 3 units
change in y-axis
-5+3=-2
(-4,-2)
Answer:
x=-2, y=-6
Step-by-step explanation:
Simple substitution.
Since y is isolated in one of the equations already, you can plug it into the second equation.
x - 2(3x) = 10
x - 6x = 10
-5x = 10
x = -2
Sub. x = -2 into 3x = y:
3(-2) = y
y = -6
