Given:
The recurring decimal is
.
To prove:
Algebraically that the recurring decimal
can be written as
.
Proof:
Let,
![x=0.47\overline{2}](https://tex.z-dn.net/?f=x%3D0.47%5Coverline%7B2%7D)
![x=0.472222...](https://tex.z-dn.net/?f=x%3D0.472222...)
Multiply both sides by 100.
...(i)
Multiply both sides by 10.
...(ii)
Subtract (i) from (ii).
![1000x-100x=472.2222...-47.2222...](https://tex.z-dn.net/?f=1000x-100x%3D472.2222...-47.2222...)
![900x=425](https://tex.z-dn.net/?f=900x%3D425)
Divide both sides by 900.
![x=\dfrac{425}{900}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B425%7D%7B900%7D)
![x=\dfrac{17}{36}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B17%7D%7B36%7D)
So,
.
Hence proved.
Answer:
y=-5/3x+5/3
Step-by-step explanation:
Answer:
To find the mean, you add all the numbers given (12, 15, 10, and 11) and then divide by the number of values in the set (in this case, 4). This is the same as finding an average. To do this, you add 12 + 15 + 10 + 11 = 48. Since you have 4 numbers, you do 48 ÷ 4, which equals 12. Therefore, the mean is 12.
Answer:
The first equals 7/10 while the other equals 6/10
Step-by-step explanation:
That's the answer
.
.
.
.
You can rewrite it as
(2/3 )•(10^(13-8))= (2/3)• 10^5 ~ 0.67•10^5=
0.67•10•10^4= 6.7•10^4
Answer $6.7•10^4