9514 1404 393
Answer:
Step-by-step explanation:
Let a and s represent the prices of adult and student tickets, respectively.
13a +12s = 211 . . . . . . ticket sales the first day
5a +3s = 65 . . . . . . . ticket sales the second day
Subtracting the first equation from 4 times the second gives ...
4(5a +3s) -(13a +12s) = 4(65) -(211)
7a = 49 . . . . . . . simplify
a = 7 . . . . . . . divide by 7
5(7) +3s = 65 . . . . substitute into the second equation
3s = 30 . . . . . . . subtract 35
s = 10 . . . . . . . divide by 3
The price of one adult ticket is $7; the price of one student ticket is $10.
Answer:
Yes by SSS because you have the same hypotenuse and same hatch marks on other sides
If you mean 46 * 3 = 138
If you mean 46 + 3 = 49
If you mean 46 - 3 = 43
If you mean<span> 46 ÷ 3 = 15.3
Hope it helped
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Answer:
The missing exponent is 5^7
Step-by-step explanation:
5^11/5^?=5^4
1. Subtract the exponents from each other.
11-4=7
2. Plug 7 in as the exponent.
5^11/5^7
3. 11-7=4 therefore, 5^11/5^7 equals 5^4.
