Annual rent=$10,800
Annual Expenses=$8,400
Rate of income=moneyt
Answer:
From the plot, one can conclude that the points (x1, y1), (x3, y3) are maxima of the function. The points (x2, y2), (x4, y4) are minima of the function. Both, these points are called extrema of the function.
Find -4 on the number line.
Go to the right 6 place values (+6)
You will find your answer
-4 (+6) = 2
2 is your answer
hope this helps
Given that x=number of days
To model the expressions we use the exponential growth given by:
y=a(b)^nx
where:
a=initial value
b=growth factor
n=24 hours
thus Colby's experiment will be:
y=50(2)^(1/2*24*x)
y=50(2)^(12x)
N/B we multiply by 24 so as to convert days into hours
b] <span>Jaquan's starts with 80 bacteria that double every 3 hours.
a=80, b=2
thus
y=80(2)^(1/3</span>×24×x<span>)
simplifying the above we get:
y=80(2)^(8x)</span>
The equation to model the situation is 
. The constant for the variation is 2250.
<h3>What is the intensity of light?</h3>
The intensity of light from a lantern varies inversely to the square of the distance from the lantern.
From the given information:
- Let y be the intensity of light, and
- x be the distance from the lantern
Then:
here, k = constant.
2.
If y = 90 W/m² when the distance x = 5m
Then:
k = 90 × 25
k = 2250
c.
The equation to model the situation by using the constant variation is:
d.
If the light intensity y = 40, then x is determined as:
x = 7.5 m
e.
The light is needed in (225 × 1000)m = 225000 km of illumination.
f.
The lantern required for the new light estimation is:
y = 2250/225000
y = 0.01 intensity
Therefore, we can conclude that to get an intensity of 1 W/m², we need to put 100 lanterns.
Learn more about intensity of light here:
brainly.com/question/19791748
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