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3 years ago

13

I have a venn diagram the two sections are multiples of 4 and the other on is even numbers but I don't know what to put in it??

Please help

1 answer:

stira [4]3 years ago

5 0

You can always use mathway to help

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65% of 40 is what number?<br>ahh this was supposed to be done yesterdayyy..

Tasya [4]

Answer:

65% of 40 is 26

6 0

3 years ago

Read 2 more answers

How do I reduce 3 25/21

Nesterboy [21]

So 25 goes into 21 how many times? 1. Add that 1 to the 3 making 4.
Then how much is left over of the 25 & 21? 4.
Making it 4 4/21

4 0

3 years ago

Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).

Elan Coil [88]

Answer: $\int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV$ = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = $\left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]$ $\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]$

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

$a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0$

Then, replacing with point P and normal vector n:

$36(x-5) + 20(y-0) + 45(z-0) = 0$

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

$z = \frac{180-36x-20y}{45}$

When z = 0:

$y = 9 + \frac{-9x}{5}$

When z=0 and y=0:

x = 5

Then, triple integral is:

$\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx$

Calculating:

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$

$\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx$

$\frac{1}{45} \int\limits^5_0 {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4} } \, dx$

$\frac{1}{45} [30375-60750+118462.5-39150]$

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$ = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0

3 years ago

Is the inequality true or false?<br><br> 8 + (2 x 4) ≥ 2^4<br><br> (^ - means exponent)

Lelu [443]

No, it is not true
8+(2x4)= 512
2^4 = 16

512 is greater than 16 but is not equal

6 0

3 years ago

How do u turn 4/10 into a fraction and percent

Delvig [45]

4/10 can be simplified to 2/5. 1/5 is equal to 20% (you probably want to memorize that) so all you have to do is multiply 20% by 2 (because of the numerator) and get 40%
So therefore 4/10 = 2/5 or 40%
P.S if you have anything over ten that needs to be a percent just multiply 10% by the numerator.

5 0

3 years ago

Read 2 more answers