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harkovskaia [24]
3 years ago
7

What is the purpose of the Ninth and Tenth Amendments? Check all of the boxes that apply.

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0
Is there a picture ??
You might be interested in
Plzz HELP FOR POINTS AND BRAINLIST ANSWER
storchak [24]

A)Plugging in our initial statement values of y = 16 when x = 10, we get:

16 = 10k

Divide each side by 10 to solve for k:

16/10=

 k = 1.6

Solve the second part of the variation equation:

Because we have found our relationship constant k = 1.6, we form our new variation equation:

y = 1.6x

Since we were given that x, we have

y = 1.6()

y = 0


B)Plugging in our initial statement values of y = 1 when x = 15, we get:

1 = 15k

Divide each side by 15 to solve for k:

1/15

=15k

k = 0.066666666666667

7 0
3 years ago
Can someone good at math give me a hand I really need some w
dedylja [7]
What is the question that u need help with
5 0
3 years ago
Are the answers correct or am I missing some?
AlekseyPX
Well,

Emily received $40.00 and then withdrew $40.00.  The final amount would be zero.

Jacoby climbed 782 feet to get to his campsite, and then descended 782 feet to get back to his car.  His final change is zero.

The Eagles mad two points, but then the Bulldogs evened it out with another two points.  The difference between the two scores would be the same.

Marcus ends up going down more than he goes up, so this is not a correct option.

The Ravens scored two points, but at the end the Raiders scored an additional 5 points, which set both teams to the same score.

Since there are an equal number of protons and electrons, and the protons have the same (but opposite) amount of charge as the electrons, the charges cancel each other out, leaving the atom with a neutral overall charge (0).
8 0
3 years ago
The table below represents the function f
alukav5142 [94]

Answer:

1

Step-by-step explanation:

I belive its one because 3^2  is 9 and 9+1 = 10

to make sure  it not just once 3^3 is 27 and 27+1=28

3 0
3 years ago
Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In​ addition, there is
Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so P(A) = 0.13.

In​ addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. P(B/A) is the probability that the person is a male, given that he/she jogs. So P(B/A) = 0.156

The Bayes theorem states that:

P(B/A) = \frac{P(A \cap B)}{P(A)}

In which P(A \cap B) is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.

So

P(A \cap B) = P(A).P(B/A) = 0.156*0.139 = 0.217

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

A probability is unusual when it is smaller than 5%.

So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

4 0
3 years ago
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