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3 years ago

What are the x-intercepts of the quadratic function? y = x2 – 3x + 2

Mathematics

1 answer:

makkiz [27]3 years ago

8 0

y = x² - 3x + 2

The x-intercepts can be take by matching the equation to 0, so,

x² - 3x + 2 = 0

Δ = b² - 4.a.c

Δ = -3² - 4 . 1 . 2

Δ = 9 - 4. 1 . 2

Δ = 1

There 2 real roots.

x = (-b +- √Δ)/2a

x' = (--3 + √1)/2.1

x'' = (--3 - √1)/2.1

x' = 4 / 2

x'' = 2 / 2

x' = 2

x'' = 1

Alternative A.

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