Answer: c = 520
Step-by-step explanation:
f(2) = 578 means that when x = 2, the value is equal to 578. We will plug these knowns in and then solve for c.
Given:
f(x) = 4x³ + 7x² - x + c
Substitute:
578 = 4(2)³ + 7(2)² - (2) + c
Distribute:
578 = 4 * 2³ + 7 * 2² - 2 + c
Raise to the power of 3 and 2:
578 = 4 * 8 + 7 * 4 - 2 + c
Multiply:
578 = 32 + 28 - 2 + c
Add:
578 = 60 - 2 + c
Subtract:
578 = 58 + c
Subtract 58 from both sides:
520 = c
Reflexive property:
c = 520
Y= x-4: gradient is 1 ; y- intercept is -4
g= -3+6
g= 3: y-intercept is 3; gradient is 0
Then you graph it
After graphing it you should find the intersection of this two line which I marked on the graph.
I’m not sure if the question is just asking you to show how these two functions are expressed on a graph or does it actually ask you to find the intersection of the two lines
But yea the coordinates of the intersection is (7,3)
Answer:
Step-by-step explanation:
F(x) results in a parabola with vertex (0,0) wich mean there is only one x-int at that point. g(x) has been shifted the grapgh of f(x) to the right by to units and down by three unites. Now our vertex lies in the point (2,-3) and since the graph was move dow i=of the x-axis we now have two different x-intercepts.
62.5%
What I did was divided 43.75 by 70 to get 0.625.
Then I moved the decimal over two places to the right to get 62.5.
First, find out how many markers in total the teacher will need.

Then, find out how many packages the teacher will need by dividing by 8 because that's how many are in each package.

Now because there is a remainder of .375 that tells us that there are not enough markers in 9 packages to give all students 3 each.
She will have to buy an additional package to give every student 3 markers each.
10 Packages are needed.