We want to recast the equation into the standard form equation for a circle centered at (h, k) with radius r. That equation is
... (x -h)² + (y -k)² = r²
Start by completing the square for both x-terms and y-terms.
... x² - 4x + y² + 4y = k
To do that, add the squares of half the coefficients of the x- and y-terms.
... x² - 4x + (-2)² + y² + 4y + 2² = k + (-2)² + 2²
... (x -2)² + (y +2)² = k + 8 = r² . . . . . this is now equal to the square of the radius, so we have
... k + 8 = 6² = 36
Subtracting 8 gives
... k = 28 . . . . . . . matches selection D)
10 x 10 x 10 = 1000 your welcome
X° = 90°-29°
= 61°
y°= 90°- 61°
= 29°
find y and x right?
The last six numbers are:
390, 395, 400, 405, 410, 415
Hope this helps☺
Since the sum of the angles of a triangle = 180°
Then <span>80º + (2x + 2)º + 5xº = 180</span>°
82° + (7x)° = 180°
(7x)° = 180° - 82°
x = 98° ÷ 7
∴ x = 14
