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3 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics

2 answers:

diamong [38]3 years ago

5 0

Answer:

97.75 seconds

Step-by-step explanation:

Kong: 15% fewer seconds than Nolan

Nolan: Kong x 115%

Kong x 115%

=85 x 115%

=97.75

<h3>Hope this helps!!!</h3><h3>:) (:</h3>

Stells [14]3 years ago

4 0

Answer: 100 sec

Step-by-step explanation:

if kolan took 85, and this is 15% fewer than nolan, nolan took longer

so 15% fewers means 100-15 - 85% of the time nolan took

so k = 0.85*n

k = 85

85 = 0.85 * n

n = 85/0.85

n = 100

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adam graded ten standardized tests with the following scores: 48, 65, 72, 86, 84, 52, 93, 97, 81, 80 which standardized test sco

SOVA2 [1]

Standardized test score that represents 70th percentile is 86.

Percentile is a comparison score between someone's score and the scores of the rest of the group. It tells the percentage of surpassed scores.

Data set = 48, 65, 72, 86, 84, 52, 93, 97, 81, 80

Sample size, n = 10

Now, arrange numbers in ascending order.

48, 52, 65, 72, 80, 81, 84, 86, 93, 97

Formula for percentile is,

Percentile = ( Number of Scores below 86 / Sample size ) x 100

Percentile = ( 7 /10 ) x 100

= (0.7) x 100

= 70%

Therefore, we can conclude that 70th percentile is = 86.

To learn more about percentile

visit; brainly.com/question/1594020

#SPJ4

4 0

1 year ago

What does it mean to be "certain" to occur?

Luden [163]

Certain means the event will happen.

Impossible means the event would never happen.

5 0

3 years ago

C=1/21.22.23+1/22.23.24+................+1/200.201.202 . = là dấu nhân

Aneli [31]

It looks like you have to find the value of the sum,

$C = \displaystyle \frac1{21\times22\times23} + \frac1{22\times23\times24} + \cdots + \frac1{200\times201\times202}$

so that the n-th term in the sum is

$\dfrac1{(21+(n-1))\times(21+n)\times(21+(n+1))} = \dfrac1{(n+20)(n+21)(n+22)}$

for 1 ≤ n ≤ 180.

We can then write the sum as

$\displaystyle C = \sum_{n=1}^{180} \frac1{(n+20)(n+21)(n+22)}$

Break up the summand into partial fractions:

$\dfrac1{(n+20)(n+21)(n+22)} = \dfrac a{n+20} + \dfrac b{n+21} + \dfrac c{n+22}$

Combine the fractions into one with a common denominator and set the numerators equal to one another:

$1 = a(n+21)(n+22) + b(n+20)(n+22) + c(n+20)(n+21)$

Expand the right side and collect terms with the same power of n :

$1 = a(n^2+43n+462)+b(n^2+42n+440) + c(n^2+41n + 420) \\\\ 1 = (a+b+c)n^2 + (43a+42b+41c)n + 462a+440b+420c$

Then

a + b + c = 0

43a + 42b + 41c = 0

462a + 440b + 420c = 1

==> a = 1/2, b = -1, c = 1/2

Now our sum is

$\displaystyle C = \sum_{n=1}^{180} \left(\frac1{2(n+20)}-\frac1{n+21}+\frac1{2(n+22)}\right)$

which is a telescoping sum. If we write out the first and last few terms, we have

C = 1/(2×21) - 1/22 + 1/(2×23)

… … + 1/(2×22) - 1/23 + 1/(2×24)

… … + 1/(2×23) - 1/24 + 1/(2×25)

… … + 1/(2×24) - 1/25 + 1/(2×26)

… … + … - … + …

… … + 1/(2×198) - 1/199 + 1/(2×200)

… … + 1/(2×199) - 1/200 + 1/(2×201)

… … + 1/(2×200) - 1/201 + 1/(2×202)

Notice the diagonal pattern of underlined and bolded terms that add up to zero (e.g. 1/(2×23) - 1/23 + 1/(2×23) = 1/23 - 1/23 = 0). So, like a telescope, the sum collapses down to a simple sum of just six terms,

C = 1/(2×21) - 1/22 + 1/(2×22) + 1/(2×201) - 1/201 + 1/(2×202)

which we simplify further to

C = 1/42 - 1/44 - 1/402 + 1/404

C = 1,115/1,042,118 ≈ 0.00106994

4 0

3 years ago

Find the value of x and y. To the nearest tenth.

Arturiano [62]

Answer:

x= 18.5 y = 14.2

Step-by-step explanation:

5 0