Subtract -6 from both sides
3x^2 + 17x + 4 - (-6) = -6 - (-6)
3x^2 + 17x + 10 = 0
factor left side of equation
(3x+2)(x+5)=0
set factors to 0
x = -2/3 OR x = -5
I would go with -5
The midpoint of the segment shown below is (1, -3/2). Option A) is the correct answer.
<u>Step-by-step explanation</u>:
The two end points of the line segments are (1,2) and (1,-5).
<u>step 1</u> :
Midpoint formula = ((x1 + x2)/2 , (y1 +y 2)/2)
<u>step 2</u> :
(x1, y1) = (1, 2)
(x2, y2) = (1, -5)
<u>step 3</u> :
Substitute the values in the midpoint formula,
Midpoint = ((1 + 1)/2 , (2 -5)/2)
= ((2/2) , (-3/2))
= (1, -3/2)
Song= sngo, sogn, gnso, gosn, gnos, snog, 6 ways ?
For squrae
area=side²
perimiter=4(side)
for circle
area=pir²
circumference=2pir
side=diameter, diameter/2=radius=side/2
find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches
areanotcovered=676-530.66=145.34 square inches not coverd
ratio of perimiter to circumferece
perimiter=4*26=104
circumference=2pir=2pi13=26pi=26*3.14=81.64
circumference to perimiter is 81.64/104=0.785
<span>15<span>(<span>6−g</span>)</span></span><span>=<span><span>(15)</span><span>(<span>6+<span>−g</span></span>)</span></span></span><span>=<span><span><span>(15)</span><span>(6)</span></span>+<span><span>(15)</span><span>(<span>−g</span>)</span></span></span></span><span>=<span>90−<span>15g</span></span></span><span>=<span><span>−<span>15g</span></span>+<span>90</span></span></span>
