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Answer:
The equation of line passing through point ( - 2 , - 3 ) and slope 1 is y = x - 1
Step-by-step explanation:
Given equation of line as :
y = x -
i.e y = x - 2
The standard equation of line is given as
y = m x + c ,
where m is the slope of the line and c is the y-intercept
Now, comparing the line , we have
Slope = m = 1
Now, The other line is perpendicular to the first line
So, from perpendicular property of line
The product of their slope = - 1
Let The slope of other line = M
So, m × M = - 1
Or, ( - 1 ) × M = - 1
or M =
∴ M = 1
So , The slope of other line = M = 1
∵ The other line is passing through point ( x , y ) = ( - 2 , - 3 )
Now, satisfying the points and slope with standard line equation
I.e y = M x + c
or, - 3 = 1 × ( - 2 ) + c
or, -3 = - 2 + c
or, - 3 + 2 = c
∴ c = - 1
So, The intercept of other line = c = - 1
Now The equation of line with slope intercept
y = 1 × x + ( - 1 )
Or, y = x - 1
Hence The equation of line passing through point ( - 2 , - 3 ) and slope 1 is y = x - 1 Answer
Answer:
Step-by-step explanation:
Given the quadratic function
we have to find the leading coefficient of given quadratic equation.
The coefficient of i.e a is known as the leading coefficient.
Comparing given equation with the standard equation, we get
a=-2