Answer:
1) For 450 minutes of calling the two plans cost the same.
2) The cost when the two plans cost the same is $56.5.
Step-by-step explanation:
The cost of both plans can be modeled by linear functions.
Plan A:
$25 plus an additional $0.07 for each minute of calls.
So, for t minutes of calls, the cost is:
Plan B:
$16 plus an additional $0.09 for each minute of calls.
So, for t minutes of calls, the cost is:
Q1: For what amount of calling do the two plans cost the same?
This is t for which:
For 450 minutes of calling the two plans cost the same.
Q2: What is the cost when the two plans cost the same?
This is A(450) or B(450), since they are the same.
The cost when the two plans cost the same is $56.5.
Answer:
H0 : μ1 = μ2
H0 : μ1 < μ2
Step-by-step explanation:
Given :
Early studiers, group 1, mean μ1
Late studiers, group 2 ; mean, μ2
To test the claim that students who study earlier have an average score that is less than the average score for students
The null hypothesis ; there is no difference in average score
H0 : μ1 = μ2
Alternative hypothesis is early studiers means is less than average score of late studiers
H0 : μ1 < μ2
Answer:
(x +3)^2 + (y -3)^2 = 3^2
Step-by-step explanation:
Your first task is to find the center.
The longest possible line of the circle goes from (-3,0) to (-3,6)
So the center is at the midpoint of these two points.
The midpoint is at (-3 - 3)/2 , (6+ 0)/2 or (-3,3)
That gives you the center of the circle.
So far what you have is
(x +3)^2 + (y -3)^2 = r^2
Now the distance of the center to the bottom point is (-3,3) to (-3,0)
r^2 = (x2 - x1)^2 + (y2 - y1)^2
x2 = - 3
x1 = - 3
y2 = 3
y1 = 0
r^2 = (-3 - -3)^2 + (3 - 0)^2
r^2 = 3^2
The entire answer is
(x +3)^2 + (y -3)^2 = 3^2
It is one out of twelve, if the twelve sides have all numbers from 1-12
