Factor yz + 6 + y +6z. z + 1)(y + 6) (z - 1)(y + 6) (z + 6)(y - 1)

1 answer:

8 0

The answer is the first one: (z+1)(y+6).

Explanation:

yz + 6 + y + 6z

= yz + y + 6 + 6z

= y(z+1) + 6(1+z)

= (z+1)(y+6)

For (z+1), you can also write (1+z), it doesn’t matter.

Hope it helps!

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Step-by-step explanation:

Look for the same stuff under the radical symbol. Here, that "stuff" is "7x". Only one answer choice has 7x under the radical.

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Here, there are no cubic factors under the radical that can be factored out—either in the problem expression or in the answer choices. If there were cubic factors, you'd want to remove them before making the comparison.

For example, ∛(56x) would be a like radical to ∛(7x) because a cubic factor of 2^3 = 8 can be removed to make it be 2∛(7x).