sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
<u>Step-by-step explanation:</u>
We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)
Given sequence is an AP with following parameters as :
So , Let's calculate how many terms are there as :
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Sum of an AP is :
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Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
Answer:
5(x+1) -2(y-3) = 0
Step-by-step explanation:
For a given line ax+by=c and point (h, k), a perpendicular line through the point can be written as ...
b(x-h) -a(y-k) = 0
A graphing calculator shows the point of intersection of the graphs of the two lines to be (x, y) = (-1, 3), so the line perpendicular to 2x+5y=5 through that point can be written ...
5(x+1) -2(y-3) = 0
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In the attached graph, the requested line is shown in black.
