4. The Commutative postulate for addition. Hope this helped you :)
Note that 1 - cos(x) = 2sin²(x/2)
⇒ lim x→0 xtan(x)/ [1 - cos(x)] =
= lim x→0 xtan(x) / 2sin²(x/2) =
= lim x→0 1/2 xtan(x) / [sin²(x/2) / (x/2)² * (x/2)²]
Also, we know that lim x→0 sin(x)/x = lim x→0 tan(x)/x = 1
So the limit is :
= 1/2 lim x→0 xtan(x) / (x²/4) =
= 1/2 lim x→0 4/x² * xtan(x) =
= 2 lim x→0 tan(x)/x =
<span>= 2.
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Answer:
Step-by-step explanation:
We first need to figure out how much money Jackie has since Pilar has the same amount of money, but in different coins. Jackie has 24 dimes and 13 quarters, so the amount of money is $2.40 + $3.25 = $5.65; therefore, Pilar has $5.65 also. In order to determine how many nickels and quarters Pilar has, we have to have a system of equations. It's up to us to write the equations we need to solve this. The first equation has to do with the NUMBER of coins Pilar has, the second has to do with the VALUE of each coin. We know that Pilar has only nickels and quarters and that she has a total of 53 coins. So the NUMBER equation is
n + q = 53
The VALUE equation relates how much each coin is worth to the total amount of money it equals:
.05n + .25q = 5.65.
Go back to the first equation and solve it for either n or q. I solved it for n:
n = 53 - q
Plug this into the second equation in place of n now to get:
.05(53 - q) + .25q = 5.65 and
2.65- .05q + .25q = 5.65 and
.20q = 3 so
q = 15. This means that there are 15 quarters. If there are 15 quarters, then there are
n + 15 = 53 nickels and
n = 38 nickels.
Well you can times both numerator and denominator 1/6 by 2 and get 2/12 so then add 2/12 and 11/12 which equals 13/12 and rounded up would be 1 1/12 have a good day
Each of the chairs cost $13, because:
70-44 = 26.
26 divided by 2 = 13.
Hope this helped!!!
