The number 15 has 2 place values.
The value in the tens place is 1.
The value in the ones place is 5.
1 tens + 5 ones = 15
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Answer:
4 x^3 + 8 x^2 - 23 x + 3
Step-by-step explanation:
Expand the following:
(2 x - 3) (2 x^2 + 7 x - 1)
| | | | 2 x | - | 3
| | 2 x^2 | + | 7 x | - | 1
| | | | -2 x | + | 3
| | 14 x^2 | - | 21 x | + | 0
4 x^3 | - | 6 x^2 | + | 0 | + | 0
4 x^3 | + | 8 x^2 | - | 23 x | + | 3:
Answer: 4 x^3 + 8 x^2 - 23 x + 3
<span>23s+56s=21
79s=21
/79 /79
s=</span><span>0.265823</span>
Answer:
the first function is correct
Answer:
4
Step-by-step explanation:
5-(4/4)=1