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2 years ago

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Brian and 3 of his friends need to collect a total of 1,548 pounds of newspaper for a recycling drive. They will each collect th

e same amount. How many pounds of newspaper will each person collect? W. 6,192 X. 4,644 Y. 387 Z. 516

2 answers:

KonstantinChe [14]2 years ago

7 0

4 people are collecting

1548 /4

387 lbs

kicyunya [14]2 years ago

4 0

I'm guessing that the answer the other one gave you is probably correct.

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2(a -3) + 4b - 2(a -b -3) + 5

Naya [18.7K]

6b + 5

Step-by-step explanation:

We begin by expounding the equation so as to remove the brackets;

2(a -3) + 4b - 2(a -b -3) + 5

2a – 6 + 4b - 2a + 2b + 6 + 5

Then we put the like terms together;

2a – 2a + 4b + 2b – 6 + 6 + 5

Now when the equation is simplified will look like this;

= 6b + 5

Learn More:

For more on simplifying expressions;

brainly.com/question/13121038

brainly.com/question/1280754

#LearnWithBrainly

5 0

2 years ago

99 POINTS................Tammi deposited $520 into a bank account that earned simple interest each year. After 5 years, she had

Olenka [21]

520 is the principal, 156 is the total interest in 5 years. Divide the 156 by 5, and you get $31.20 per year. divide: 31.2 / 520 = 0.06. convert that to a fraction, and you get the answer: 6%

4 0

2 years ago

Read 2 more answers

Police plan to enforce speed limits by using radar traps at four different locations within the city limits. The radar traps at

dalvyx [7]

Answer:

The probability that the person gets a speeding ticket is 0.27

Step-by-step explanation:

The probability that the person receives a speeding ticket is the probability that the person passes through any of the speed limits and the radar is operating at that time.

Let $P(L_1)$ is the probability that the person passes through radar $L_{1}$ and it is operating at that time is

$P(L_{1})=P(1)\times P(2)$

Where

P(1) is the probability of person passes through $L_{1}$

P(2) is probability that the radar is operating

$P(L_1)=0.2\times 0.4=0.08$

Similarly the probabilities are calculated for other radars in the similar manner as

$P(L_2)=0.1\times 0.3=0.03$

$P(L_3)=0.5\times 0.2=0.1$

$P(L_4)=0.2\times 0.3=0.06$

Thus the reuired probability of the reuired event is

$P(E)=P(L_1)+P(L_2)+P(L_3)+P(L_4)\\\\P(E)=0.08+0.03+0.1+0.06=0.27$

8 0

2 years ago

I know the selected answer is correct but I'm not too sure how to get that answer.

Kryger [21]

$\tt{ Hey \: there , \: Mr.Panda \: ! }$ ;)

♨ $\large{ \tt{ E \: X \: P \: L \: A \: N \: A \: T \: I\: O \: N}}:$

⤻ Before solving the given question , you should know the answer of these questions :

✺How do you find the hypotenuse , perpendicular and base when the angle ( $\theta \: , \alpha \: ,\beta$ ) is given ?

⇾ The longest side , which is the opposite side of right angle is the hypotenuse ( h ). There are two other sides , the opposite and the adjacent. The naming of these sides depends upon which angle is involved. The opposite is the side opposite the angle involved and it is called the perpendicular ( p ) . The adjacent us the side next to the angle involved ( buy not the hypotenuse ) and it is called the base ( b ).

☄ $\large{ \tt{REMEMBER}} :$

$\bf{ \sin \theta = \frac{opposite}{hypotenuse} = \frac{perpendicular}{hypotenuse} }$

$\bf{ \cos\theta = \frac{adjacent}{hypotenuse} = \frac{base}{hypotenuse} }$

$\bf{ \tan \theta = \frac{opposite}{adjacent} = \frac{perpendicular}{base} }$

In the above cases , $\theta$ is taken as the angle of reference.

♪ Our Q/A part ends up here! Let's start solving the question :

❈ $\large{ \tt{GIVEN}} :$

Perpendicular ( p ) = ? , Hypotenuse ( h ) = 18 & base ( b ) = 16

✧ $\large{ \tt{TO \: FIND} : }$

Value of tan $\theta$

✎ $\large{ \tt{SOLUTION}} :$

Firstly , Finding the value of perpendicular ( p ) using Pythagoras theorem :

❃ $\boxed{ \sf{ {h}^{2} = {p}^{2} + {b}^{2} }}$ [ Pythagoras theorem ]

$\large{ ⇢ \sf{p}^{2} + {b}^{2} = {h}^{2} }$

$\large{⇢ \sf{ {p}^{2} = {h}^{2} - {b}^{2} }}$

$\large{ ⇢\sf{ {p}^{2} = {18}^{2} - {16}^{2} }}$

$\large{⇢ \sf{ {p}^{2} = 324 - 256}}$

$\large{⇢ \sf{ {p}^{2} = 68}}$

$\large{⇢ \sf{p = \sqrt{68}}}$

$\large{ ⇢\sf{p = \boxed{ \tt{2 \sqrt{17}}} }}$

Okey, We found out the perpendicular i.e $\tt{2 \sqrt{17}}$ . Now , We know :

❊ $\large{ \sf{ \tan \theta} = \frac{perpendicular}{base} }$

$\large {\tt{↬ \: tan \theta = \frac{2 \sqrt{17} }{16}}}$

$\large{ \tt{ ↬ tan \theta = \frac{ \cancel{2} \: \sqrt{17} }{ \cancel{16} \: \: 8} }}$

$\large{ \tt{ ↬ \boxed{ \tt{tan \theta = \frac{ \sqrt{17} }{8}}}}}$

⟿ $\boxed{ \boxed{ \tt{OUR\: FINAL \: ANSWER : \boxed{ \underline{ \bf{ \frac{ \sqrt{17} }{8}}}}}}}$

۵ Yay! We're done!

♕ $\large\tt{RULE \: OF \:SUCCESS }:$

Never lose hope & keep on working ! ✔

ツ Hope I helped!

☃ Have a wonderful day / evening! ☼

# StayInAndExplore ☂

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3 0

2 years ago

Read 2 more answers

Choose SSS, SAS, or neither to compare

Oliga [24]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

According to above figure, we can conclude that :

The given triangles are congruent by SSS criteria.

8 0

2 years ago