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3 years ago

Anisa went to Dicks Sporting good and bought

Mathematics

2 answers:

g100num [7]3 years ago

8 0

Answer:

$492

Step-by-step explanation:

MissTica3 years ago

5 0

Answer: $492

The work:

Anisa got $116

58 x 2 = 116

Emma got $376

94 x 4 = 376

Add them: $492

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Mr. Rico's small business is starting to make a profit. His costs last week were -$352. His profit last week was $22. How many t

MrRa [10]

Answer:

The Answer is -16

Step-by-step explanation:

The equation to this would be -352 / 22, which would give you 16, hope this helped!

5 0

3 years ago

Can someone please help me answer my question? I need an explanation as well!!! WILL GIVE BRAINLIEST IF CORRECT!!!

Anni [7]

Answer:

The blanks are both 8

Step-by-step explanation:

This is because of the distribution property. Since there is parenthesis, this means that the 8 is being distributed to both the 5 and -2.

4 0

3 years ago

Read 2 more answers

HELP!!! There is a photo please quickly!!

Nostrana [21]

Answer:

∆y = 9

∆x = 6

Slope = 3/2 or 1.5

It looks like you erased it, but you had the answer correct on your paper.

Step-by-step explanation:

7 0

1 year ago

Li deposited $17,500 into a bank account that earned simple interest each year. After 2 years, he had earned $2975 in interest.

Nimfa-mama [501]

Let x is the interest rate

$17,500 * 2 * x = <span>$2975
</span>$35,000x = $2,975
x = $2,975/$35,000
<span>x = 0.085

0.085 * 100 = 8.5%

Answer: annual interest rate was 8.5%

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3 0

3 years ago

Read 2 more answers

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

3 years ago