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Ghella [55]
2 years ago
8

Anisa went to Dicks Sporting good and bought

Mathematics
2 answers:
g100num [7]2 years ago
8 0

Answer:

$492

Step-by-step explanation:

MissTica2 years ago
5 0

Answer: $492

The work:

Anisa got $116

      58 x 2 = 116

Emma got $376

      94  x 4 = 376

Add them: $492

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3 years ago
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A box in a college bookstore contains books, and each book in the box is a history book, an English book or a science bok. If 1/
Rufina [12.5K]
1/2 are science because if you make 1/3, 2/6 + 1/6= 3/6. 3/6 = 1/2. 1/2 and 1/2 make a whole.
7 0
3 years ago
A number is between 16 and 21. It has prime factors of 2, and 3. What is the number?
Advocard [28]

Answer:18

Step-by-step explanation: 18=2.3.3

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3 years ago
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Alchen [17]

Answer:

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y=-2,0

Step-by-step explanation:

8 0
2 years ago
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a particular city had a population of 24,000 in 1900 and a population of 29,000 in 1920. Assuming that its population continues
DerKrebs [107]

Answer:

It will have a population of 61,779 in 2000.

Step-by-step explanation:

The population for the city, in t years after 1900, can be modeled by a exponential function with constant growth rate in the following format:

P(t) = P(0)(1+r)^{t}

In which P(0) is the population in 1900 and r is the growth rate.

Population of 24,000 in 1900

This means that P(0) = 24000

Population of 29,000 in 1920.

1920 is 1920 - 1900 = 20 years after 1900.

This means that P(20) = 29000. So

P(t) = P(0)(1+r)^{t}

29000 = 24000(1+r)^{20}

(1+r)^{20} = \frac{29000}{24000}

\sqrt[20]{(1+r)^{20}} = \sqrt[20]{\frac{29000}{24000}}

1 + r = 1.0095

So

P(t) = P(0)(1+r)^{t}

P(t) = 24000(1.0095)^{t}

What population will it have in 2000

2000 is 2000 - 1900 = 100 years after 1900. So this is P(100).

P(t) = 24000(1.0095)^{t}

P(100) = 24000(1.0095)^{100} = 61779

It will have a population of 61,779 in 2000.

4 0
3 years ago
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