All categories

2 years ago

If m rst = 70, m qst = 2x, and m qsr = 3x-10 what is the m qsr

Mathematics

2 answers:

mel-nik [20]2 years ago

5 0

Answer:

m∠rst =70°

m∠qst=2x

m∠qsr=3x-10°

It means two rays originate from point s.Diagram is attached below.

→m∠qsr=m∠rst + m∠qst

→ 3x-10°=70°+2x

→3x-2x=70°+10°

→x=80°

m∠qsr=3 ×80°-10

=240°-10°

=230°

Anna [14]2 years ago

4 0

Answer:

m qsr = 62°

Step-by-step explanation:

From my understanding, the question states 3 angles of a triangle

All 3 angles of a triangle are equal to 180°.

Step 1: Find x

70 + 2x + 3x - 10 = 180°

70 + 5x - 10 = 180

5x = 180 - 60

x = 120/5

x = 24°

Step 2: Find angle qsr

m qsr = 3x - 10

m qsr = 3(24) - 10

m qsr = 62°

You might be interested in

3.41 repeating as a simplified fraction

HACTEHA [7]

Answer:

3 37/90

Step-by-step explanation:

You didn't ask for the work. Hope this helps.

Marking as Brainliest is much appreciated.

4 0

2 years ago

The lines have the same slopes and the same y-intercepts.

MissTica

Answer:

B is the correct answer

7 0

2 years ago

Read 2 more answers

How many minutes are in 2 3/5 hours

Temka [501]

156 minutes are in 2 and 3/5 of an hour.

4 0

2 years ago

Read 2 more answers

A multiple-choice examination has 20 questions, each with five possible answers, only one of which is correct. Suppose that one

kari74 [83]

Answer:

The probability that the student answers at least seventeen questions correctly is $8.03\times 10^{-10}$ .

Step-by-step explanation:

Let the random variable X represent the number of correctly answered questions.

It is provided all the questions have five options with only one correct option.

Then the probability of selecting the correct option is,

$P(X)=p=\frac{1}{5}=0.20$

There are n = 20 question in the exam.

It is also provided that a student taking the examination answers each of the questions with an independent random guess.

Then the random variable can be modeled by the Binomial distribution with parameters n = 20 and p = 0.20.

The probability mass function of X is:

$P(X=x)={20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x};\ x =0,1,2,3...$

Compute the probability that the student answers at least seventeen questions correctly as follows:

$P(X\geq 17)=P (X=17)+P (X=18)+P (X=19)+P (X=20)$

$=\sum\limits^{20}_{x=17}{{20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x}}\\\\=0.00000000077+0.000000000032+0.00000000000084+0.000000000000042\\\\=0.000000000802882\\\\=8.03\times10^{-10}$

Thus, the probability that the student answers at least seventeen questions correctly is $8.03\times 10^{-10}$ .

4 0

3 years ago

Arithmetic series HELP PLEASE

KIM [24]

Answer:

5050

Step-by-step explanation:

∑_{n=1 to 50} (4n-1)

a1=4×1-1=3

a2=4×2-1=7

a3=4×3-1=11

......................

a50=4×50-1=199

n=50

Sn=n/2(a1+an)

S50=50/2(3+199)=50/2×202=50×101=5050

5 0

3 years ago

Read 2 more answers