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natta225 [31]
3 years ago
11

Check out if I'm right Plz explain..if u have a different answer

Mathematics
2 answers:
Ronch [10]3 years ago
8 0

Answer:

A C

Step-by-step explanation:

A

A is true.The numerator does have 3 terms. The constant term (the 3 at the end) is still a term and counts as a term.

B

A constant term does not count as a coefficient so b is not right, just as you have indicated by not underlining it.

C

C is true. In fact, 2 is the leading coefficent of the denominator.

D

Either A is true or D is, but I don't think they both are. You need a modifier to claim that D is true. If the statement said the numerator has <em>at least </em>2 terms then both A and D would be true. Without the at least, you have to pick one and the one I choose is A

E

This is the tough one. Very sticky. You would think it is true, but it isn't. A constant term is not a coefficient. Coefficients only count when they are with "x"s.

zepelin [54]3 years ago
7 0

Answer:

  • The numerator has 3 terms.
  • The denominator includes a coefficient of 2.

and possibly (check your definitions)

  • The denominator includes a coefficient of 4.
  • The numerator includes a coefficient of 3.

Step-by-step explanation:

Apparently, the exercise is to count terms and identify coefficients.

A term is a constant or the product of a constant and some constellation of variables.

A coefficient is a multiplier of the variable(s) of interest. Any term or expression multiplying only 1 (not any expression involving the variable(s) of interest), may be called a "constant coefficient."

Consider the expression ...

... axy +bx +cy +d

If we consider the variables x and y to be the variables of interest, then "d" is a "constant coefficient" and "a", "b", and "c" are the coefficients in the first three terms.

If we consider y to be the variable of interest, then "ax" and "c" are coefficients (or you could say (ax+c) is the coefficient of y) and (bx+d) is the "constant coefficient."

<em>Your Mileage May Vary</em>

Other sources identify a coefficient as the multiplier of variables. Those sources would ignore any constants or other expressions that don't multiply variables of interest. Check your reference text to see how it defines <em>coefficient</em>.

_____

<em>Comment on your answer choices</em>

You have selected contradictory answers: the numerator term count is 3; the numerator term count is 2. (The <em>denominator</em> term count is 2, but that is not on the list.)

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<h2>The missing measures of the angles are:</h2>

m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

<u>Given</u>:

m\angle Z = 138^{\circ}

<em><u>Note the following:</u></em>

  • An equilateral triangle has all its three angles equal to each other. Each angle = 60^{\circ}.
  • This implies that, since \triangle WXY is equilateral, therefore, m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}

  • Base angles of an isosceles triangle are congruent to each other.
  • This implies that, since \triangle WZY is isosceles, therefore, m\angle 3 = \angle 5

Applying the above stated, let's find the measure of each angle:

  • Find m\angle 1

m\angle 1 = 60^{\circ} (an angle in an equilateral triangle equals 60 degrees)

  • Find m\angle 2

m\angle 2 = 60 - m \angle 3

m\angle 2 = 60 -\frac{1}{2}(180 - 138) (Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)

m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}

  • Find m\angle 3 and m\angle 5 (base angles of isosceles triangle WZY)

m\angle 3 =  \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)

m\angle 3 =  \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}

m\angle3 = m\angle 5 (base angles of isosceles triangle are congruent)

Therefore,

m\angle5 = 21^{\circ}

  • Find m\angle 4

m\angle 4 = 60 - m\angle 5

Substitute

m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}

The missing measures of the angles are:

m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

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